(a) Can endothermic chemical reactions be spontaneous? (b) Can a process be spontaneous at one temperature and nonspontaneous at a different temperature? (c) Water can be decomposed to form hydrogen and oxygen, and the hydrogen and oxygen can be recombined to form water. Does this mean that the processes are thermodynamically reversible? (d) Does the amount of work that a system can do on its surroundings depend on the path of the process?

Short Answer

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(a) Yes, endothermic chemical reactions can be spontaneous if the entropy change (∆S) is positive and large enough, causing ∆G to be negative at certain temperatures. (b) A process can be spontaneous at one temperature and nonspontaneous at another temperature due to changes in the Gibbs free energy (∆G) as temperature changes. (c) The decomposition and recombination of water does not necessarily mean these processes are thermodynamically reversible; conditions for reversibility must be met. (d) The amount of work that a system can do on its surroundings depends on the path of the process, as work and heat transferred differ depending on the specific path taken between initial and final states.

Step by step solution

01

Answer (a)

Yes, endothermic chemical reactions can be spontaneous. The spontaneity of a reaction depends on the Gibbs free energy change (∆G), which is defined as ∆G = ∆H - T∆S, where ∆H is the enthalpy change, T is temperature, and ∆S is the entropy change. A reaction is spontaneous if ∆G is negative. Endothermic reactions have a positive ∆H; however, if the entropy change (∆S) is positive and large enough, the reaction will be spontaneous at certain temperatures.
02

Answer (b)

Yes, a process can be spontaneous at one temperature and nonspontaneous at another temperature. This is because the spontaneity of a process is determined by the Gibbs free energy change (∆G), which is dependent on both the enthalpy change (∆H) and the entropy change (∆S), as well as the temperature (T). As the temperature changes, the terms T∆S and ∆H in the equation ∆G = ∆H - T∆S can have different magnitudes and signs, causing the value of ∆G to change. If ∆G is negative, the process is spontaneous, and if ∆G is positive, the process is nonspontaneous.
03

Answer (c)

The decomposition of water into hydrogen and oxygen, and the recombination of hydrogen and oxygen into water, can be considered as two different processes. Just because these two processes can occur does not necessarily mean that they are thermodynamically reversible. In a thermodynamically reversible process, the system is in equilibrium with its surroundings throughout the process, and a small change in a variable can reverse the process. For the water decomposition and recombination processes to be thermodynamically reversible, the conditions for reversibility must be met, which is not always the case in reality.
04

Answer (d)

Yes, the amount of work that a system can do on its surroundings depends on the path of the process. Work, heat, and internal energy are state functions that depend on the initial and final states of the system. However, the amounts of work and heat transferred differ depending on the specific path taken between those states. A system might do more work along one path than another, even if the initial and final states are the same. For example, during an isothermal expansion, the work done by an ideal gas on its surroundings depends on whether the expansion occurs reversibly or irreversibly.

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