Consider a system consisting of an ice cube. (a) Under what conditions can the ice cube melt reversibly? If the ice cube melts reversibly, is \(\Delta H\) zero for the process?

Short Answer

Expert verified
In conclusion, an ice cube can melt reversibly if it is heated infinitesimally slowly at the melting point (0°C or 273.15 K) while maintaining equilibrium with its surroundings, and the surrounding temperature is infinitesimally higher than the melting point. During this process, the enthalpy change (\(\Delta H\)) is positive and non-zero as the ice cube absorbs heat for the phase transition from solid to liquid.

Step by step solution

01

Determine conditions for reversible melting

A process can be considered reversible if it proceeds infinitesimally slowly, maintaining thermodynamic equilibrium between the system (ice cube) and its surroundings throughout the entire process. For the ice cube to melt reversibly, it must be heated at the same rate it is melting, keeping the system and surroundings in equilibrium. Let's consider an ice cube at its melting point, which is 0°C (273.15 K) at atmospheric pressure. To make the melting process reversible, the temperature of the surroundings should be infinitesimally higher than the melting point. This will provide a gradual supply of heat to the ice cube, allowing it to melt slowly while maintaining equilibrium with its surroundings.
02

Calculate the change in enthalpy \(\Delta H\)

Enthalpy change, \(\Delta H\), is the amount of heat absorbed or released during a process at constant pressure. In the case of the ice cube melting, it absorbs heat from its surroundings, which is converted into internal energy, leading to a phase transition from solid to liquid. The enthalpy change for melting is also known as the enthalpy of fusion, which is the amount of heat required to convert 1 mole of a substance from the solid phase to the liquid phase at its melting point and constant pressure. For water, the enthalpy of fusion is approximately 6.01 kJ/mol. As the ice cube is absorbing heat to transform from solid to liquid during the reversible melting process, the enthalpy change, \(\Delta H\), is positive and non-zero.
03

Conclusion

To sum up, an ice cube can melt reversibly if it is heated infinitesimally slowly, maintaining thermodynamic equilibrium between the system (ice cube) and its surroundings. The surroundings should have a temperature infinitesimally higher than the melting point of the ice cube (0°C or 273.15 K). During the reversible melting process, the enthalpy change, \(\Delta H\), is positive and non-zero, since the ice cube absorbs heat to transform from solid to liquid.

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Most popular questions from this chapter

The element gallium (Ga) freezes at \(29.8^{\circ} \mathrm{C},\) and its molar enthalpy of fusion is \(\Delta H_{\text { fus }}=5.59 \mathrm{k} \mathrm{k} / \mathrm{mol}\) . (a) When molten gallium solidifies to Ga(s) at its normal melting point, is \(\Delta S\) positive or negative? (b) Calculate the value of \(\Delta S\) when 60.0 g of Ga(l) solidifies at \(29.8^{\circ} \mathrm{C}\) .

Using the data in Appendix \(C\) and given the pressures listed, calculate \(K_{p}\) and \(\Delta G\) for each of the following reactions: $$ \begin{array}{l}{\text { (a) } \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)} \\ {P_{\mathrm{N}_{2}}=2.6 \mathrm{atm}, P_{\mathrm{H}_{2}}=5.9 \mathrm{atm}, R_{\mathrm{NH}_{3}}=1.2 \mathrm{atm}} \\ {\text { (b) } 2 \mathrm{N}_{2} \mathrm{H}_{4}(g)+2 \mathrm{NO}_{2}(g) \longrightarrow 3 \mathrm{N}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(g)} \\ {P_{\mathrm{N}_{2} \mathrm{H}_{4}}=P_{\mathrm{NO}_{2}}=5.0 \times 10^{-2} \mathrm{atm}} \\ {P_{\mathrm{N}_{2}}=0.5 \mathrm{atm}, P_{\mathrm{H}_{2} \mathrm{O}}=0.3 \mathrm{atm}}\\\\{\text { (c) }{\mathrm{N}_{2} \mathrm{H}_{4}(g) \longrightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2}(g)}} \\ {P_{\mathrm{N}_{2} \mathrm{H}_{4}}=0.5 \mathrm{atm}, P_{\mathrm{N}_{2}}=1.5 \mathrm{atm}, P_{\mathrm{H}_{2}}=2.5 \mathrm{atm}}\end{array} $$

An ice cube with a mass of 20 \(\mathrm{g}\) at \(-20^{\circ} \mathrm{C}\) (typical freezer temperature) is dropped into a cup that holds 500 \(\mathrm{mL}\) of hot water, initially at \(83^{\circ} \mathrm{C} .\) What is the final temperature in the cup? The density of liquid water is 1.00 \(\mathrm{g} / \mathrm{mL}\) ; the specific heat capacity of ice is \(2.03 \mathrm{J} / \mathrm{g}-\mathrm{C}\) ; the specific heat capacity of liquid water is \(4.184 \mathrm{J} / \mathrm{g}-\mathrm{C} ;\) the enthalpy of fusion of water is 6.01 \(\mathrm{k} \mathrm{J} / \mathrm{mol} .\)

The value of \(K_{a}\) for nitrous acid \(\left(\mathrm{HNO}_{2}\right)\) at \(25^{\circ} \mathrm{C}\) is given in Appendix D. (a) Write the chemical equation for the equilibrium that corresponds to \(K_{a \cdot}\) (b) By using the value of \(K_{a},\) calculate \(\Delta G^{\circ}\) for the dissociation of nitrous acid in aqueous solution. (c) What is the value of \(\Delta G\) at equilibrium? (d) What is the value of \(\Delta G\) when \(\left[\mathrm{H}^{+}\right]=5.0 \times 10^{-2} M\) \(\left[\mathrm{NO}_{2}^{-}\right]=6.0 \times 10^{-4} M,\) and \(\left[\mathrm{HNO}_{2}\right]=0.20 \mathrm{M} ?\)

Indicate whether each statement is true or false. (a) The entropy of the universe increases for any spontaneous process. (b) The entropy change of the system is equal and opposite that of the surroundings for any irreversible process. (c) The entropy of the system must increase in any spontaneous process. (a) The entropy change for an isothermal process depends on both the absolute temperature and the amount of heat reversibly transferred.

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