(a) What is the difference between a state and a microstate of a system? (b) As a system goes from state A to state \(B,\) its entropy decreases. What can you say about the number of microstates corresponding to each state? (c) In a particular spontaneous process, the number of microstates available to the system decreases. What can you conclude about the sign of \(\Delta S_{\text { surr }}\) ?

Short Answer

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(a) A state is a set of macroscopic properties defining a system's condition (e.g., temperature, pressure, volume), while a microstate is a specific microscopic configuration of particles associated with a particular state, having the same macroscopic properties but varying positions and velocities of particles. (b) If entropy decreases when going from state A to state B, the number of microstates for state B is less than for state A, as entropy is related to microstates through \(S = k_{B} \ln{W}\). (c) If microstates decrease in a spontaneous process, \(\Delta S_{\text{sys}}\) is negative, and for the process to be spontaneous, \(\Delta S_{\text{surr}}\) must be positive, indicating an increase in the entropy of the surroundings.

Step by step solution

01

Part(a): Define State and Microstate

A state of a system is a specific set of macroscopic properties that uniquely define its condition, such as temperature, pressure, and volume. On the other hand, a microstate is a specific microscopic configuration of particles associated with a particular state. Each microstate has the same macroscopic properties (i.e., it corresponds to the same state), but the individual positions and velocities of the particles may vary.
02

Part(b): Entropy and Number of Microstates

When the system transitions from state A to state B with a decrease in entropy, it implies that the number of possible microstates for the system has decreased. This is because entropy is a measure of the disorder or randomness in a system, and it is directly related to the number of microstates through the formula \(S = k_{B} \ln{W}\), where \(S\) is the entropy, \(k_{B}\) is the Boltzmann constant, and \(W\) is the number of microstates. If the entropy decreases, then the number of microstates corresponding to state B would be less than the number of microstates corresponding to state A.
03

Part(c): Sign of \(\Delta S_{\text{surr}}\) in a Spontaneous Process

If the number of microstates available to the system decreases during a spontaneous process, it implies that the entropy of the system, \(S_{\text{sys}}\), decreases. For a process to be spontaneous, the total entropy change, which includes both the system and its surroundings, must be positive: \(\Delta S_{\text{total}} = \Delta S_{\text{sys}} + \Delta S_{\text{surr}} > 0\). Since \(\Delta S_{\text{sys}}\) is negative (due to decreasing microstates), for the process to be spontaneous, we must have \(\Delta S_{\text{surr}}\) positive (i.e., the entropy of the surroundings must increase) to satisfy the inequality and maintain a positive total entropy change.

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Most popular questions from this chapter

Predict the sign of \(\Delta S_{\text { sys }}\) for each of the following processes: (a) Molten gold solidifies. (b) Gaseous \(C l_{2}\) dissociates in the stratosphere to form gaseous Cl atoms. (c) Gaseous CO reacts with gaseous \(\mathrm{H}_{2}\) to form liquid methanol, \(\mathrm{CH}_{3} \mathrm{OH} .(\mathbf{d})\) Calcium phosphate precipitates upon mixing \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) and \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}(a q)\)

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