Draw the structural formulas for three isomers of pentane, \(\mathrm{C}_{5} \mathrm{H}_{12} .\)

Short Answer

Expert verified
The three isomers of pentane are: 1. n-Pentane: \(\mathrm{CH}_{3}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{3}\) 2. Isopentane (2-methylbutane): \(\mathrm{CH}_{3}\mathrm{-}\mathrm{CH\ (}\mathrm{CH}_{3})\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{3}\) 3. Neopentane (2,2-dimethylpropane): \(\mathrm{C\ (}\mathrm{CH}_{3})_{4}\)

Step by step solution

01

Draw the first isomer - n-pentane

Draw a straight chain of 5 carbon atoms bonded to each other. This straight chain is known as n-pentane, where n denotes a normal (straight) chain. \(\mathrm{CH}_{3}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{3}\) There are no branches in this structure, and all carbon atoms are connected in a linear pattern.
02

Draw the second isomer - isopentane (2-methylbutane)

In this isomer, we will create a branch in the carbon skeleton by moving one carbon atom from the end of the chain to the 2nd carbon atom position in the original pentane chain. This will form a new compound, isopentane (also known as 2-methylbutane). \(\mathrm{CH}_{3}\mathrm{-}\mathrm{CH\ (}\mathrm{CH}_{3})\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{3}\) In this structure, there is a single branch on the second carbon atom, creating a new isomer.
03

Draw the third isomer - neopentane (2,2-dimethylpropane)

For the third isomer, create two branches by moving two carbon atoms from the end of the original pentane chain to the 2nd carbon atom position. This will form the compound neopentane, also known as 2,2-dimethylpropane. \(\mathrm{C\ (}\mathrm{CH}_{3})_{4}\) In this structure, the central carbon atom is bonded to four methyl groups (\(\mathrm{CH}_3\)), creating another unique isomer of pentane. The three isomers of pentane are: 1. n-Pentane (\(\mathrm{CH}_{3}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{3}\)) 2. Isopentane (2-methylbutane): \(\mathrm{CH}_{3}\mathrm{-}\mathrm{CH\ (}\mathrm{CH}_{3})\mathrm{-}\mathrm{CH}_{2}\mathrm{-}\mathrm{CH}_{3}\) 3. Neopentane (2,2-dimethylpropane): \(\mathrm{C\ (}\mathrm{CH}_{3})_{4}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The nucleus of 6 Li is a powerful absorber of neutrons. It exists in the naturally occurring metal to the extent of 7.5\(\%\) . In the era of nuclear deterrence, large quantities of lithium were processed to remove 6 Li for use in hydrogen bomb production. The lithium metal remaining after removal of 6 Li was sold on the market. (a) What are the compositions of the nuclei of 6 Li and 7 Li? (b) The atomic masses of 6 Li and 7 Li are 6.015122 and 7.016004 amu, respectively. A sample of lithium depleted in the lighter isotope was found on analysis to contain 1.442\(\%\) 6 Li. What is the average atomic weight of this sample of the metal?

Predict the chemical formula for the ionic compound formed by (a) \(\mathrm{Ca}^{2+}\) and \(\mathrm{Br}^{-},(\mathbf{b}) \mathrm{K}^{+}\) and \(\mathrm{CO}_{3}^{2-},(\mathbf{c}) \mathrm{Al}^{3+}\) and \(\mathrm{CH}_{3} \mathrm{COO}^{-},(\mathbf{d}) \mathrm{NH}_{4}^{+}\) and \(\mathrm{SO}_{4}^{2-},(\mathbf{e}) \mathrm{Mg}^{2+}\) and \(\mathrm{PO}_{4}^{3-}\) .

Give the name or chemical formula, as appropriate, for each of the following binary molecular substances: \((\mathbf{a}) \mathrm{SF}_{6},(\mathbf{b}) \mathrm{IF}_{5}(\mathbf{c}) \mathrm{XeO}_{3} (\mathbf{d}) \text {dinitrogen tetroxide}, (\mathbf{e}) \text {hydrogen cyanide}, (\mathbf{f})\text{ tetraphosphorus hexasulfide.}\)

(a) Which two of the following are isotopes of the same element: \(\frac{31}{16} \mathrm{X}, \frac{31}{15} \mathrm{X}, \frac{32}{16} \mathrm{X}\) ? (b) What is the identity of the element whose isotopes you have selected?

The explosion of an atomic bomb releases many radioactive isotopes, including strontium- \(90 .\) Considering the location of strontium in the periodic table, suggest a reason for the fact that this isotope is particularly dangerous for human health.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free