By using the data in Appendix E, determine whether each of the following substances is likely to serve as an oxidant or a reductant: (a) \(\mathrm{Cl}_{2}(g),(\mathbf{b}) \mathrm{MnO}_{4}^{-}(a q,\) acidic solution), (c) \(\mathrm{Ba}(s),(\mathbf{d}) \mathrm{Zn}(s) .\)

Short Answer

Expert verified
Based on the standard reduction potentials from Appendix E, the given substances are likely to act as follows: (a) \(\mathrm{Cl}_{2}(g)\) - Oxidant (b) \(\mathrm{MnO}_{4}^{-}(a q, \text {acidic solution})\) - Oxidant (c) \(\mathrm{Ba}(s)\) - Reductant (d) \(\mathrm{Zn}(s)\) - Reductant

Step by step solution

01

Find the standard reduction potentials for each substance

Consult Appendix E to find the standard reduction potential values (\(E^\circ\)) for each substance. Look for the half-reactions that directly involve the given substances. (a) For \(\mathrm{Cl}_{2}(g)\), find the half-reaction: \(\mathrm{Cl}_{2}(g)+2e^{-}\rightarrow 2 \mathrm{Cl}^{-}(a q)\). The \(E^\circ\) value for this half-reaction is 1.36 V. (b) For \(\mathrm{MnO}_{4}^{-}(a q, \text {acidic solution})\), find the half-reaction: \(\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 e^{-}\rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}\). The \(E^\circ\) value for this half-reaction is 1.51 V. (c) For \(\mathrm{Ba}(s)\), find the half-reaction: \(\mathrm{Ba}^{2+}+2 e^{-}\rightarrow \mathrm{Ba}(s)\). The \(E^\circ\) value for this half-reaction is -2.92 V. (d) For \(\mathrm{Zn}(s)\), find the half-reaction: \(\mathrm{Zn}^{2+}+2 e^{-}\rightarrow \mathrm{Zn}(s)\). The \(E^\circ\) value for this half-reaction is -0.76 V.
02

Determine whether each substance acts as an oxidant or reductant

A substance will act as an oxidant if its reduction potential is high, indicating that it has a high tendency to gain electrons (undergo reduction). Conversely, a substance will act as a reductant if its reduction potential is low, indicating that it has a high tendency to lose electrons (undergo oxidation). (a) \(\mathrm{Cl}_{2}(g)\): Since the reduction potential is 1.36 V, a high positive value, \(\mathrm{Cl}_{2}(g)\) is likely to act as an oxidant. (b) \(\mathrm{MnO}_{4}^{-}(a q, \text {acidic solution})\): Since the reduction potential is 1.51 V, another high positive value, \(\mathrm{MnO}_{4}^{-}\) is also likely to act as an oxidant. (c) \(\mathrm{Ba}(s)\): With a reduction potential of -2.92 V, a low negative value, \(\mathrm{Ba}(s)\) is likely to act as a reductant. (d) \(\mathrm{Zn}(s)\): The reduction potential of -0.76 V, another low negative value, indicates that \(\mathrm{Zn}(s)\) is likely to act as a reductant.
03

Conclusion

Based on the data in Appendix E, the substances will likely act as oxidants or reductants as follows: (a) \(\mathrm{Cl}_{2}(g)\) - Oxidant (b) \(\mathrm{MnO}_{4}^{-}(a q, \text {acidic solution})\) - Oxidant (c) \(\mathrm{Ba}(s)\) - Reductant (d) \(\mathrm{Zn}(s)\) - Reductant

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Most popular questions from this chapter

For each of the following balanced oxidation-reduction reactions, (i) identify the oxidation numbers for all the elements in the reactants and products and (ii) state the total number of electrons transferred in each reaction. $$ \begin{array}{l}{\text { (a) } 2 \mathrm{MnO}_{4}^{-}(a q)+3 \mathrm{S}^{2-}(a q)+4 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 3 \mathrm{S}(s)+} \\ {\quad 2 \mathrm{MnO}_{2}(s)+8 \mathrm{OH}^{-}(a q)} \\ {\text { (b) } 4 \mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{Cl}_{2} \mathrm{O}_{7}(g)+2 \mathrm{OH}^{-}(a q) \longrightarrow 2 \mathrm{ClO}_{2}^{-}(a q)+} \\ {\quad 5 \mathrm{H}_{2} \mathrm{O}(l)+4 \mathrm{O}_{2}(g)} \\\\{\text { (c) } \mathrm{Ba}^{2+}(a q)+2 \mathrm{OH}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q)+2 \mathrm{ClO}_{2}(a q) \longrightarrow} \\ {\quad \mathrm{Ba}\left(\mathrm{ClO}_{2}\right)_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g)}\end{array} $$

(a) Write the reactions for the discharge and charge of a nickel-cadmium (nicad) rechargeable battery. (b) Given the following reduction potentials, calculate the standard emf of the cell: $$ \begin{array}{r}{\operatorname{Cd}(\mathrm{OH})_{2}(s)+2 \mathrm{e}^{-} \longrightarrow \mathrm{Cd}(s)+2 \mathrm{OH}^{-}(a q)} \\\ {E_{\mathrm{red}}^{\circ}=-0.76 \mathrm{V}}\end{array} $$ $$ \begin{array}{r}{\mathrm{NiO}(\mathrm{OH})(s)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{e}^{-} \longrightarrow \mathrm{Ni}(\mathrm{OH})_{2}(s)+\mathrm{OH}^{-}(a q)} \\\ {E_{\mathrm{red}}^{\circ}=+0.49 \mathrm{V}}\end{array} $$ (c) A typical nicad voltaic cell generates an emf of \(+1.30 \mathrm{V}\) . Why is there a difference between this value and the one you calculated in part (b)? (d) Calculate the equilibrium constant for the overall nicad reaction based on this typical emf value.

A voltaic cell is constructed with all reactants and products in their standard states. Will the concentration of the reactants increase, decrease, or remain the same as the cell operates?

Complete and balance the following equations, and identify the oxidizing and reducing agents. (Recall that the O atoms in hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\) , have an atypical oxidation state.) $$ \begin{array}{l}{\text { (a) } \mathrm{NO}_{2}^{-}(a q)+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q) \longrightarrow \mathrm{Cr}^{3+}(a q)+\mathrm{NO}_{3}^{-}(a q)} \\ \quad {\text { (acidic solution) }} \\\ {\text { (b) } \mathrm{S}(s)+\mathrm{HNO}_{3}(a q) \rightarrow \mathrm{H}_{2} \mathrm{SO}_{3}(a q)+\mathrm{N}_{2} \mathrm{O}(g)} \\ {\quad(\text { acidic solution })} \\ {\text { (c) } \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{CH}_{3} \mathrm{OH}(a q) \longrightarrow \mathrm{HCOOH}(a q)+} \\\ \quad {\mathrm{Cr}^{3+}(a q)(\text { acidic solution })} \\ {\text { (d) } \operatorname{BrO}_{3}^{-}(a q)+\mathrm{N}_{2} \mathrm{H}_{4}(g) \longrightarrow \mathrm{Br}^{-}(a q)+\mathrm{N}_{2}(g)} \\ \quad {\text { (acidic solution) }} \\ {\text { (e) } \mathrm{NO}_{2}^{-}(a q)+\mathrm{Al}(s) \longrightarrow \mathrm{NH}_{4}^{+}(a q)+\mathrm{AlO}_{2}^{-}(a q)} \\ \quad {\text { (basic solution) }} \\\ {\text { (f) } \mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{ClO}_{2}(a q) \rightarrow \mathrm{ClO}_{2}^{-}(a q)+\mathrm{O}_{2}(g)} \\ \quad {\text { (basic solution) }}\end{array} $$

(a) What is meant by the term oxidation? (b) On which side of an oxidation half-reaction do the electrons appear? (c) What is meant by the term oxidant? (d) What is meant by the term oxidizing agent?

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