(a) Assuming standard conditions, arrange the following in order of increasing strength as oxidizing agents in acidic solution: \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{Cu}^{2+}, \mathrm{Cl}_{2}, \mathrm{O}_{2} .\) (b) Arrange the following in order of increasing strength as reducing agents in acidic solution: \(\text {Zn,}\) \(\mathrm{I}^{-}, \mathrm{Sn}^{2+}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{Al} .\)

Short Answer

Expert verified
(a) The oxidizing agents in order of increasing strength in acidic solution are: \(\mathrm{Cu}^{2+}, \mathrm{O}_{2}, \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}, \mathrm{Cl}_{2},\) and \(\mathrm{H}_{2} \mathrm{O}_{2}.\) (b) The reducing agents in order of increasing strength in acidic solution are: \(\mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{I}^{-}, \mathrm{Sn}^{2+}, \text {Zn},\) and \(\mathrm{Al}.\)

Step by step solution

01

Find the standard reduction potentials for the given half-cell reactions.

First, we need to find the standard reduction potentials (E°) for the given half-cell reactions. We can do this by consulting a table of standard reduction potentials. (a) For the oxidizing agents in acidic solution: - \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+ 14\mathrm{H}^{+}+ 6\mathrm{e}^{-} \longrightarrow 2\mathrm{Cr}^{3+} + 7H_{2}O\), E° = 1.33 V - \(\mathrm{H}_{2} \mathrm{O}_{2} + 2\mathrm{H}^{+} + 2\mathrm{e}^{-} \longrightarrow 2\mathrm{H}_{2}\mathrm{O}\), E° = 1.78 V - \(\mathrm{Cu}^{2+} + 2\mathrm{e}^{-} \longrightarrow \mathrm{Cu}\), E° = 0.34 V - \(\mathrm{Cl}_{2} + 2\mathrm{e}^{-} \longrightarrow 2\mathrm{Cl}^-\), E° = 1.36 V - \(\mathrm{O}_{2} + 4\mathrm{H}^{+} + 4\mathrm{e}^{-} \longrightarrow 2\mathrm{H}_{2}\mathrm{O}\), E° = 1.23 V (b) For the reducing agents in acidic solution: - \(\text {Zn} + 2\mathrm{H}^{+} \longrightarrow \mathrm{Zn}^{2+}+ \mathrm{H}_{2}\), E° = -0.76 V - \(2\mathrm{I}^{-} \longrightarrow \mathrm{I}_{2}+ 2\mathrm{e}^{-}\), E° = 0.54 V - \(\mathrm{Sn}^{2+} + 2\mathrm{e}^{-} \longrightarrow \mathrm{Sn}\), E° = -0.14 V - \(\mathrm{H}_{2} \mathrm{O}_{2} + 2\mathrm{H}^{+} + 2\mathrm{e}^{-} \longrightarrow 2\mathrm{H}_{2}\mathrm{O}\), E° = 1.78 V - \(\mathrm{Al} + 3\mathrm{H}^{+} \longrightarrow \mathrm{Al}^{3+} + \frac{3}{2}\mathrm{H}_{2}\), E° = -1.66 V
02

Arrange the substances in order of increasing strength as oxidizing agents in acidic solution.

Now that we have the standard reduction potentials, we can arrange the given substances in order of increasing strength as oxidizing agents. We're looking for the substances with the most positive E° values, as these will be the strongest oxidizing agents. (a) The oxidizing agents in order of increasing strength are as follows: - \(\mathrm{Cu}^{2+}\) (0.34 V) - \(\mathrm{O}_{2}\) (1.23 V) - \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\) (1.33 V) - \(\mathrm{Cl}_{2}\) (1.36 V) - \(\mathrm{H}_{2} \mathrm{O}_{2}\) (1.78 V)
03

Arrange the substances in order of increasing strength as reducing agents in acidic solution.

Similarly, for reducing agents, we're looking for the substances with the most negative E° values, as these will be the strongest reducing agents. (b) The reducing agents in order of increasing strength are as follows: - \(\mathrm{H}_{2} \mathrm{O}_{2}\) (1.78 V) - \(\mathrm{I}^{-}\) (0.54 V) - \(\mathrm{Sn}^{2+}\) (-0.14 V) - \(\text {Zn}\) (-0.76 V) - \(\mathrm{Al}\) (-1.66 V)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using standard reduction potentials (Appendix E), calculate the standard emf for each of the following reactions: $$ \begin{array}{l}{\text { (a) } \mathrm{Cl}_{2}(g)+2 \mathrm{I}^{-}(a q) \longrightarrow 2 \mathrm{Cl}^{-}(a q)+\mathrm{I}_{2}(s)} \\ {\text { (b) } \mathrm{Ni}(s)+2 \mathrm{Ce}^{4+}(a q) \longrightarrow \mathrm{Ni}^{2+}(a q)+2 \mathrm{Ce}^{3+}(a q)} \\ {\text { (c) } \mathrm{Fe}(s)+2 \mathrm{Fe}^{3+}(a q) \longrightarrow 3 \mathrm{Fe}^{2+}(a q)} \\ {\text { (d) } 2 \mathrm{NO}_{3}^{-}(a q)+8 \mathrm{H}^{+}(a q)+3 \mathrm{Cu}(s) \longrightarrow 2 \mathrm{NO}(g)+} \\ \quad {4 \mathrm{H}_{2} \mathrm{O}(l)+3 \mathrm{Cu}^{2+}(a q)}\end{array} $$

A voltaic cell is constructed that uses the following reaction and operates at \(298 \mathrm{K} :\) $$ \mathrm{Zn}(s)+\mathrm{Ni}^{2+}(a q) \longrightarrow \mathrm{Zn}^{2+}(a q)+\mathrm{Ni}(s) $$ (a) What is the emf of this cell under standard conditions? (b) What is the emf of this cell when \(\left[\mathrm{Ni}^{2+}\right]=3.00 M\) and \(\left[\mathrm{Zn}^{2+}\right]=0.100 \mathrm{M} ?(\mathbf{c})\) What is the emf of the cell when \(\left[\mathrm{Ni}^{2+}\right]=0.200 \mathrm{M}\) and \(\left[\mathrm{Zn}^{2+}\right]=0.900 \mathrm{M} ?\)

(a) In the Nernst equation, what is the numerical value of the reaction quotient, Q, under standard conditions? (b) Can the Nernst equation be used at temperatures other than room temperature?

Hydrogen gas has the potential for use as a clean fuel in reaction with oxygen. The relevant reaction is $$ 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l) $$ Consider two possible ways of utilizing this reaction as an electrical energy source: (i) Hydrogen and oxygen gases are combusted and used to drive a generator, much as coal is currently used in the electric power industry; (ii) hydrogen and oxygen gases are used to generate electricity directly by using fuel cells that operate at \(85^{\circ} \mathrm{C}\) . (a) Use data in Appendix C to calculate \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) for the reaction. We will assume that these values do not change appreciably with temperature. (b) Based on the values from part (a), what trend would you expect for the magnitude of \(\Delta G\) for the reaction as the temperature increases? (c) What is the significance of the change in the magnitude of \(\Delta G\) with temperature with respect to the utility of hydrogen as a fuel? (d) Based on the analysis here, would it be more efficient to use the combustion method or the fuel-cell method to generate electrical energy from hydrogen?

Predict whether the following reactions will be spontaneous in acidic solution under standard conditions: (a) oxidation of \(S n\) to \(S n^{2+}\) by \(I_{2}(\) to form I \(),\) (b) reduction (a) oxidation of \(\mathrm{Sn}\) to \(\mathrm{Sn}^{2+}\) by \(\mathrm{I}_{2}\) \(( \text { to form } \mathrm{I})\); (b) reduction of \(\mathrm{Ni}^{2+}\) to \(\mathrm{Ni}\) by \(\mathrm{I}^{-}(\) to form \(\mathrm{I}_{2}),(\mathbf{c})\) reduction of \(\mathrm{Ce}^{4+}\) to \(\mathrm{Ce}^{3+}\) by \(\mathrm{H}_{2} \mathrm{O}_{2}\) (d) reduction of \(\mathrm{Cu}^{2+}\) to Cu by \(\operatorname{Sn}^{2+}(\) to form \( \mathrm{Sn}^{4+} )\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free