(a) Suppose that an alkaline battery was manufactured using cadmium metal rather than zinc. What effect would this have on the cell emf? (b) What environmental advantage is provided by the use of nickel-metal hydride batteries over nickel-cadmium batteries?

Short Answer

Expert verified
Using cadmium instead of zinc in an alkaline battery increases the cell emf by 0.36 V, resulting in a higher cell emf, as the standard electrode potential of cadmium is less negative than that of zinc. The environmental advantage of using nickel-metal hydride (NiMH) batteries over nickel-cadmium (NiCd) batteries is the absence of toxic cadmium in NiMH batteries. Cadmium can cause environmental issues by contaminating soil and water, leading to health problems for plants, animals, and humans. NiMH batteries have a lower environmental impact due to the absence of cadmium.

Step by step solution

01

Part (a): Determine the effect on cell emf using cadmium rather than zinc

For part (a), we will compare the standard electrode potentials of zinc and cadmium, since this will determine the change in cell emf. Let's find out the standard electrode potentials for zinc and cadmium. Standard electrode potential for zinc: Zn -> Zn^2+ + 2e-; \(E^0_{Zn}\) = -0.76 V Standard electrode potential for cadmium: Cd -> Cd^2+ + 2e-; \(E^0_{Cd}\) = -0.40 V Now, let's determine the change in cell emf when using cadmium instead of zinc.
02

Calculate the difference in electrode potentials

First, we need to find the difference between the standard electrode potentials of zinc and cadmium. Difference in standard electrode potentials: \(ΔE^0 = E^0_{Cd} - E^0_{Zn}\) \(ΔE^0 = -0.40 V - (-0.76 V) = 0.36 V\)
03

Determine the effect on cell emf

Since the standard electrode potential of cadmium is less negative than that of zinc, substituting zinc with cadmium will make the cell emf more positive (increase the cell emf) by 0.36V. This means that the battery using cadmium will have a higher cell emf than the one using zinc.
04

Part (b): Environmental advantages of nickel-metal hydride batteries over nickel-cadmium batteries

For part (b), discussing the environmental advantage of using nickel-metal hydride (NiMH) batteries over nickel-cadmium (NiCd) batteries: The primary environmental advantage of using NiMH batteries instead of NiCd batteries is that NiMH batteries don't contain toxic cadmium. Cadmium is highly toxic and can cause various environmental issues. Cadmium can contaminate the soil and water, which leads to its presence in plants, animals, and humans, causing serious health issues. When NiCd batteries are not disposed of properly, they can leak cadmium into the environment, making it essential that they are recycled properly. On the other hand, NiMH batteries, which use a metal hydride instead of cadmium, are considered more environmentally friendly due to the absence of toxic cadmium. While still requiring proper disposal and recycling, the overall environmental impact of NiMH batteries is less severe than that of NiCd batteries.

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Most popular questions from this chapter

Indicate whether the following balanced equations involve oxidation-reduction. If they do, identify the elements that undergo changes in oxidation number. $$ \begin{array}{l}{\text { (a) } \mathrm{PBr}_{3}(l)+3 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{H}_{3} \mathrm{PO}_{3}(a q)+3 \mathrm{HBr}(a q)} \\ {\text { (b) } \mathrm{NaI}(a q)+3 \mathrm{HNOl}(a q) \longrightarrow \mathrm{NaIO}_{3}(a q)+3 \mathrm{HCl}(a q)} \\ {\text { (c) } 3 \mathrm{SO}_{2}(g)+2 \mathrm{HNO}_{3}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow} \\ {\quad 3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{NO}(g)}\end{array} $$

A voltaic cell similar to that shown in Figure 20.5 is constructed. One electrode half-cell consists of a silver strip placed in a solution of \(\mathrm{AgNO}_{3},\) and the other has an iron strip placed in a solution of \(\mathrm{FeCl}_{2}\) . The overall cell reaction is $$ \mathrm{Fe}(s)+2 \mathrm{Ag}^{+}(a q) \longrightarrow \mathrm{Fe}^{2+}(a q)+2 \mathrm{Ag}(s) $$ (a) What is being oxidized, and what is being reduced? (b) Write the half-reactions that occur in the two half-cells. (c) Which electrode is the anode, and which is the cathode? (d) Indicate the signs of the electrodes. (e) Do electrons flow from the silver electrode to the iron electrode or from the iron to the silver? (f) In which directions do the cations and anions migrate through the solution?

(a) Assuming standard conditions, arrange the following in order of increasing strength as oxidizing agents in acidic solution: \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{Cu}^{2+}, \mathrm{Cl}_{2}, \mathrm{O}_{2} .\) (b) Arrange the following in order of increasing strength as reducing agents in acidic solution: \(\text {Zn,}\) \(\mathrm{I}^{-}, \mathrm{Sn}^{2+}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{Al} .\)

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(a) What is meant by the term oxidation? (b) On which side of an oxidation half-reaction do the electrons appear? (c) What is meant by the term oxidant? (d) What is meant by the term oxidizing agent?

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