Write balanced nuclear equations for the following transformations: \((\mathbf{a})\) bismuth-213 undergoes alpha decay; \((\mathbf{b})\) nitrogen-13 undergoes electron capture; \((\mathbf{c})\) technicium-98 undergoes electron capture; \((\mathbf{d})\) gold-188 decays by positron emission.

Short Answer

Expert verified
The balanced nuclear equations for the given transformations are: (a) Bismuth-213 undergoes alpha decay: \( ^{213}_{83}Bi \rightarrow ^{209}_{81}Tl + ^{4}_{2}He \) (b) Nitrogen-13 undergoes electron capture: \( ^{13}_{7}N + ^{0}_{-1}e \rightarrow ^{13}_{6}C \) (c) Technetium-98 undergoes electron capture: \( ^{98}_{43}Tc + ^{0}_{-1}e \rightarrow ^{98}_{42}Mo \) (d) Gold-188 decays by positron emission: \( ^{188}_{79}Au \rightarrow ^{188}_{78}Pt + ^{0}_{+1}e \)

Step by step solution

01

(a) Bismuth-213 undergoes alpha decay

An alpha decay involves the emission of an alpha particle (consisting of two protons and two neutrons). In this case, bismuth-213 will decay and emit an alpha particle. The balanced nuclear equation is given by: ^213_83Bi -> ^209_81Tl + ^4_2He Here, we have balanced the mass numbers (213 = 209 + 4) and the atomic numbers (83 = 81 + 2).
02

(b) Nitrogen-13 undergoes electron capture

In electron capture, a nucleus captures one of its inner electrons. This electron combines with a proton to form a neutron. In this case, nitrogen-13 undergoes electron capture. The balanced nuclear equation is given by: ^13_7N + ^0_{-1}e -> ^13_6C Here, we have balanced the mass numbers (13 = 13) and the atomic numbers (7 - 1 = 6).
03

(c) Technetium-98 undergoes electron capture

In this case, technetium-98 also undergoes electron capture. The balanced nuclear equation is given by: ^98_43Tc + ^0_{-1}e -> ^98_42Mo Here, we have balanced the mass numbers (98 = 98) and the atomic numbers (43 - 1 = 42).
04

(d) Gold-188 decays by positron emission

In positron emission, a nucleus emits a positron (an antimatter particle with a positive charge equal in magnitude to the charge of an electron). In this case, gold-188 goes through positron emission. The balanced nuclear equation is given by: ^188_79Au -> ^188_78Pt + ^0_{+1}e Here, we have balanced the mass numbers (188 = 188) and the atomic numbers (79 = 78 + 1).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alpha Decay
Alpha decay is a type of radioactive decay where an unstable nucleus emits an alpha particle, which consists of two protons and two neutrons — essentially a helium nucleus. This process transmutes the original element into a new element with an atomic number decreased by two and a mass number decreased by four. It's one of the most common forms of natural radioactive decay.

For example, with bismuth-213 undergoing alpha decay, we write the equation:
\[^{213}_{83}Bi \rightarrow ^{209}_{81}Tl + ^4_2He\].
This shows that bismuth-213 loses an alpha particle and becomes thallium-209 in the process. Such equations are crucial in understanding how radioactive materials change over time and can be used to calculate the half-lives of radioactive isotopes.
Electron Capture
Electron capture is another fascinating process in nuclear chemistry where an inner orbital electron is captured by the nucleus of its own atom. During this interaction, a proton in the nucleus is transformed into a neutron while the electron essentially 'disappears', resulting in the emission of an electron neutrino.

For both nitrogen-13 and technetium-98 examples, the equations are as follows:
\[^{13}_7N + ^0_{-1}e \rightarrow ^{13}_6C\]
and
\[^{98}_{43}Tc + ^0_{-1}e \rightarrow ^{98}_{42}Mo\].
These reactions demonstrate the conversion of one element to another through the reduction of the atomic number by one without changing the mass number. Electron capture is particularly important in the field of nuclear medicine, where it's used in diagnostic imaging.
Positron Emission
Positron emission, also known as beta plus decay (\(\beta^+\) decay), occurs when a proton in a nucleus is transformed into a neutron and a positron, which is the antiparticle of an electron. The positron is expelled from the atom, and its ejection helps to conserve energy, momentum, and angular momentum in the system.

The equation for gold-188 decaying by positron emission looks like this:
\[^{188}_{79}Au \rightarrow ^{188}_{78}Pt + ^0_{+1}e\].
This process decreases the atomic number by one while the mass number remains unchanged. Positron emission is used in positron emission tomography (PET), a powerful medical imaging technique that provides three-dimensional images of metabolic processes in the body.
Nuclear Chemistry
Nuclear chemistry dives into the heart of atoms, where it examines and explains the reactions and processes that occur within the nucleus. It encompasses a broad range of topics, including radioactive decay, nuclear fission and fusion, and radiochemical techniques.

Understanding nuclear chemistry is vital not only for solving nuclear equations but also for harnessing nuclear energy, developing new medical treatments, and managing radioactive materials safely. It allows scientists to predict the behavior of radioactive elements, design nuclear reactors, and understand the effects of radiation on biological systems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which type or types of nuclear reactors have these characteristics? \(\begin{array}{l}{\text { (a) Does not use a secondary coolant }} \\ {\text { (b) Creates more fissionable material than it consumes }} \\ {\text { (c) Uses a gas, such as He or } \mathrm{CO}_{2}, \text { as the primary coolant }}\end{array}\)

A \(26.00-\mathrm{g}\) sample of water containing tritium, \(_{1}^{3} \mathrm{H},\) emits \(1.50 \times 10^{3}\) beta particles per second. Tritium is a weak beta emitter with a half-life of 12.3 yr. What fraction of all the hydrogen in the water sample is tritium?

Indicate the number of protons and neutrons in the following nuclei: \((\mathbf{a}) _{53}^{129} I,(\mathbf{b})^{138} \mathrm{Ba},(\mathbf{c})\) neptunium\(-237 .\)

Why is it important that radioisotopes used as diagnostic tools in nuclear medicine produce gamma radiation when they decay? Why are alpha emitters not used as diagnostic tools?

Iodine-131 is a convenient radioisotope to monitor thyroid activity in humans. It is a beta emitter with a half-life of 8.02 days. The thyroid is the only gland in the body that uses iodine. A person undergoing a test of thyroid activity drinks a solution of Nal, in which only a small fraction of the iodide is radioactive. (a) Why is Nal a good choice for the source of iodine? (b) If a Geiger counter is placed near the person's thyroid (which is near the neck) right after the sodium iodide solution is taken, what will the data look like as a function of time? (c) A normal thyroid will take up about 12\(\%\) of the ingested iodide in a few hours. How long will it take for the radioactive iodide taken up and held by the thyroid to decay to 0.01\(\%\) of the original amount?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free