The nuclear masses of \(^{7}\mathrm{Be},^{9} \mathrm{Be},\) and \(^{10} \mathrm{Be}\) are \(7.0147,9.0100\) and 10.0113 amu, respectively. Which of these nuclei has the largest binding energy per nucleon?

Short Answer

Expert verified
The isotope with the largest binding energy per nucleon is \(^{10}\mathrm{Be}\), with a binding energy per nucleon of 3.52 MeV/nucleon.

Step by step solution

01

Calculate the Binding Energy for Each Isotope

To calculate the binding energy, we will use the following formula: Binding Energy = (Total Mass of Individual Nucleons - Nuclear Mass) × 931.5 MeV We also know that the nuclear mass of \(^{7}\mathrm{Be},^{9} \mathrm{Be},\) and \(^{10}\mathrm{Be}\) are \(7.0147, 9.0100\) and 10.0113 amu, respectively. For each isotope, we need to first calculate the total mass of individual nucleons (protons and neutrons) and then calculate the binding energies.
02

Total Mass of Individual Nucleons

For \(^{7}\mathrm{Be}\): Number of protons = 4 (it's beryllium) Number of neutrons = 7 - 4 = 3 Total mass of individual nucleons = (mass of proton × number of protons) + (mass of neutron × number of neutrons) = (4 × 1.0073) + (3 × 1.0087) = 7.0349 amu For \(^{9}\mathrm{Be}\): Number of protons = 4 (it's beryllium) Number of neutrons = 9 - 4 = 5 Total mass of individual nucleons = (mass of proton × number of protons) + (mass of neutron × number of neutrons) = (4 × 1.0073) + (5 × 1.0087) = 9.0373 amu For \(^{10}\mathrm{Be}\): Number of protons = 4 (it's beryllium) Number of neutrons = 10 - 4 = 6 Total mass of individual nucleons = (mass of proton × number of protons) + (mass of neutron × number of neutrons) = (4 × 1.0073) + (6 × 1.0087) = 10.0491 amu
03

Calculate the Binding Energies

For \(^{7}\mathrm{Be}\): Binding Energy = (7.0349 - 7.0147) × 931.5 = 18.83 MeV For \(^{9}\mathrm{Be}\): Binding Energy = (9.0373 - 9.0100) × 931.5 = 25.38 MeV For \(^{10}\mathrm{Be}\): Binding Energy = (10.0491 - 10.0113) × 931.5 = 35.20 MeV
04

Calculate the Binding Energy per Nucleon

For \(^{7}\mathrm{Be}\): Binding Energy per Nucleon = 18.83 MeV / 7 = 2.69 MeV/nucleon For \(^{9}\mathrm{Be}\): Binding Energy per Nucleon = 25.38 MeV / 9 = 2.82 MeV/nucleon For \(^{10}\mathrm{Be}\): Binding Energy per Nucleon = 35.20 MeV / 10 = 3.52 MeV/nucleon
05

Determine the Isotope with the Largest Binding Energy per Nucleon

Comparing the binding energy per nucleon values, we can see that: \(^{10}\mathrm{Be}\) has the largest binding energy per nucleon at 3.52 MeV/nucleon.

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