Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) hexamminechromium(III) nitrate (b) tetraamminecarbonatocobalt(III) sulfate (c) dichlorobis(ethylenediamine)platinum(IV) bromide (d) potassium diaquatetrabromovanadate(III) (e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II)

Short Answer

Expert verified
(a) \[ [Cr(NH_3)_6] (NO_3)_3 \] (b) \[ [Co(NH_3)_4CO_3](SO_4)_2 \] (c) \[ [PtCl_2(en)_2] (Br)_4 \] (d) \[ K [V(H_2O)_2Br_4] \] (e) \[ [Zn(en)_2] [HgI_4] \]

Step by step solution

01

(a) hexamminechromium(III) nitrate

The compound consists of a hexamminechromium(III) complex cation and nitrate anion. The coordination sphere refers to the central ion (in this case, chromium) surrounded by six ammine (NH3) ligands. The oxidation state of chromium is given as (III). For each of the chromium complex cations there are three nitrate (NO3-) anions to balance the charge. Formula: \[ [Cr(NH_3)_6] (NO_3)_3 \]
02

(b) tetraamminecarbonatocobalt(III) sulfate

The compound consists of a tetraamminecarbonatocobalt(III) complex cation and sulfate anion. The coordination sphere refers to the central ion (cobalt) surrounded by four ammine (NH3) ligands and one carbonate (CO3^2-) ligand. The oxidation state of cobalt is given as (III). For each of the cobalt complex cations there are two sulfate (SO4^2-) anions to balance the charge. Formula: \[ [Co(NH_3)_4CO_3](SO_4)_2 \]
03

(c) dichlorobis(ethylenediamine)platinum(IV) bromide

The compound consists of a dichlorobis(ethylenediamine)platinum(IV) complex cation and bromide anion. The coordination sphere refers to the central ion (platinum) surrounded by two chlorine ligands and two ethylenediamine (en) ligands. The oxidation state of platinum is given as (IV). For each of the platinum complex cations there are four bromide (Br^-) anions to balance the charge. Formula: \[ [PtCl_2(en)_2] (Br)_4 \]
04

(d) potassium diaquatetrabromovanadate(III)

The compound consists of a potassium cation and a diaquatetrabromovanadate(III) complex anion. The coordination sphere refers to the central ion (vanadium) surrounded by two water (H2O) ligands and four bromine ligands. The oxidation state of vanadium is given as (III). For each of the vanadium complex anions, there is one potassium cation to balance the charge. Formula: \[ K [V(H_2O)_2Br_4] \]
05

(e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II)

The compound consists of a bis(ethylenediamine)zinc(II) complex cation and a tetraiodomercurate(II) complex anion. The coordination sphere for the cation refers to the central ion (zinc) surrounded by two ethylenediamine (en) ligands. The oxidation state of zinc is given as (II). For the anion, the coordination sphere refers to the central ion (mercury) surrounded by four iodine ligands. The oxidation state of mercury is given as (II). There is one zinc complex cation for each mercury complex anion to balance the charge. Formula: \[ [Zn(en)_2] [HgI_4] \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordination Chemistry
Coordination chemistry revolves around the study of coordination compounds, which are substances that have a central metal atom or ion bonded to a group of molecules or anions called ligands. These ligands can be neutral molecules like water (H2O) or ammonia (NH3), or charged ions like chloride (Cl-). The ligands are bonded to the metal center through coordinate covalent bonds, where both electrons in the bond originate from the same atom, usually the ligand.

These complexes can have various geometries such as square planar, tetrahedral, or octahedral based on the number and spatial arrangement of ligands around the central metal. Coordination compounds are described using coordination numbers, which tell us the number of ligand-donor atoms bonded to the metal ion. For instance, in hexamminechromium(III) nitrate, chromium has a coordination number of six because it is surrounded by six ammonia molecules.

In coordination chemistry, it's also crucial to understand the naming of compounds. For example, 'hexammine' signifies six ammonia ligands, and 'dichlorobis' suggests two chlorine ligands and two molecules of a bidentate ligand like ethylenediamine. Understanding these naming conventions is key to writing correct formulas for such compounds.
Writing Chemical Formulas
Writing chemical formulas for coordination compounds requires knowledge of the complex's composition and the rules for naming such structures. The central metal is written first, followed by the ligands within square brackets to denote the coordination sphere. Ligands are generally written alphabetically, and their number is indicated by prefixes such as di-, tri-, tetra-, etc. Multi-atomic ligands like ethylenediamine are often encapsulated in parentheses.

When writing these formulas, it is also important to indicate the oxidation state of the metal, which is given in Roman numerals within the name and placed after the metal within the chemical formula. For example, the (III) in hexamminechromium(III) nitrate indicates that chromium has a +3 oxidation state. The charge of the entire coordination complex is balanced by counter-ions, like nitrate (NO3-) or sulfate (SO42-), which are written outside the brackets. If necessary, these counter-ions are written as multiples, to balance the charge of the complex, as seen in the chemical formula \[ [Cr(NH3)6] (NO3)3 \].
Oxidation States
The oxidation state (also called oxidation number) is a concept in chemistry that describes the degree of oxidation of an atom in a chemical compound. It is a hypothetical charge that an atom would have if all its bonds to atoms of different elements were 100% ionic.

Oxidation states are typically represented by integers, which can be positive, negative, or zero. In coordination compounds, knowing the oxidation state of the central metal ion is essential to deduce the correct formula of the complex. For example, in the coordination compound dichlorobis(ethylenediamine)platinum(IV) bromide, the IV after platinum indicates that platinum is in the +4 oxidation state. The overall charge on the coordination sphere must be balanced by the counter-ions present outside the brackets.

Calculation of oxidation states within coordination complexes can be done by using the known charges of the ligands and applying the rule that the sum of the oxidation states within a neutral molecule must be zero, or must match the charge if the molecule is an ion. This method helps in determining the number of counter-ions needed to balance the charge of the complex as seen in the provided exercise.

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Most popular questions from this chapter

Polydentate ligands can vary in the number of coordination positions they occupy. In each of the following, identify the polydentate ligand present and indicate the probable number of coordination positions it occupies: (a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}(0-\mathrm{phen})\right] \mathrm{Cl}_{3}\) (b) \(\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{Br}\) (c) \([\mathrm{Ca}(\mathrm{EDTA})]^{2-}\) (d) \(\left[\mathrm{Zn}(\mathrm{en})_{2}\right]\left(\mathrm{ClO}_{4}\right)_{2}\)

The ion \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\) has one unpaired electron, whereas \(\left[\mathrm{Fe}(\mathrm{NCS})_{6}\right]^{3-}\) has five unpaired electrons. From these results, what can you conclude about whether each complex is high spin or low spin? What can you say about the placement of \(\mathrm{NCS}^{-}\) in the spectrochemical series?

Determine if each of the following metal complexes is chiral and therefore has an optical isomer: (a) tetrahedral \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2} \mathrm{Cl}_{2}\right],(\mathbf{b})\) octahedral trans-[Ru(bipy) \()_{2} \mathrm{Cl}_{2} ],(\mathbf{c})\) octahedral cis-[Ru(bipy) \(_{2} \mathrm{Cl}_{2} ] .\)

A manganese complex formed from a solution containing potassium bromide and oxalate ion is purified and analyzed. It contains \(10.0 \% \mathrm{Mn}, 28.6 \%\) potassium, \(8.8\%\) carbon, and 29.2\(\%\) bromine by mass. The remainder of the compound is oxygen. An aqueous solution of the complex has about the same electrical conductivity as an equimolar solution of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] .\) Write the formula of the compound, using brackets to denote the manganese and its coordination sphere.

(a) If a complex absorbs light at \(610 \mathrm{nm},\) what color would you expect the complex to be? (b) What is the energy in joules of a photon with a wavelength of 610 \(\mathrm{nm} ?\) (c) What is the energy of this absorption in \(\mathrm{kJ} / \mathrm{mol}\) ?

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