Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 24: Problem 22

(a) Is the compound \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}\) saturated or unsaturated? Explain. (b) What is wrong with the formula \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{3} ?\)

Short Answer

Expert verified
(a) The compound \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}\) is unsaturated because it contains a double bond between the second and third carbon atoms. (b) The problem with the formula \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}=\mathrm{CH}_{3}\) is that it shows a double bond between the third and fourth carbon atoms, but both of these carbon atoms still have two hydrogen atoms bonded to them, which is incorrect. The correct formula should be \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}=\mathrm{CH}_{2}\).

Step by step solution

01

Understand saturated and unsaturated compound

A saturated compound is a compound in which all carbon atoms are bonded to the maximum number of hydrogen atoms possible, with no double or triple bonds between carbon atoms. An unsaturated compound contains one or more double or triple bonds between carbon atoms, which results in the possibility of adding more hydrogen atoms to the compound.
02

Analyse the given compound \(\mathrm{CH}_{3}\mathrm{CH}=\mathrm{CH}_{2}\)

In this formula, the carbon atoms are represented by the letter 'C', and the hydrogen atoms are represented by the letter 'H'. There is a double bond between the second and third carbon atom (indicated by the equals sign). This double bond results in lesser hydrogen atoms being bonded to the second and third carbon atoms, as seen by the subscript 1 next to both hydrogen atoms. Thus, the total hydrogen atoms in the given compound are six.
03

Determine if the compound is saturated or unsaturated

As we have already identified a double bond between the second and third carbon atoms in the compound \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}\), it indicates that the compound is unsaturated. An unsaturated compound contains one or more double or triple bonds between carbon atoms. Answer (a): The compound \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}\) is unsaturated because it contains a double bond between the second and third carbon atoms.
04

Analyse the given formula \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}=\mathrm{CH}_{3}\)

In this formula, there are four carbon atoms and eight hydrogen atoms. However, there seems to be a double bond between the third and fourth carbon atoms. This would result in lesser hydrogen atoms being bonded to the third and fourth carbon atoms.
05

Identify the issue with the formula \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}=\mathrm{CH}_{3}\)

The issue with the formula \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}=\mathrm{CH}_{3}\) is that it shows a double bond between the third and fourth carbon atoms, but both of these carbon atoms still have two hydrogen atoms bonded to them. If there were a double bond between these carbon atoms, both of them should have one hydrogen atom each. The correct formula should be \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}=\mathrm{CH}_{2}\). Answer (b): The problem with the formula \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}=\mathrm{CH}_{3}\) is that it shows a double bond between the third and fourth carbon atoms, but both of these carbon atoms still have two hydrogen atoms bonded to them, which is incorrect.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Can a DNA strand bind to a complementary RNA strand? Explain.

Describe two ways in which the octane number of a gasoline consisting of alkanes can be increased.

The protein ribonuclease \(A\) in its native, or most stable, form is folded into a compact globular shape: (a) Does the native form have a lower or higher free energy than the denatured form, in which the protein is an extended chain? (b) What is the sign of the system's entropy change in going from the denatured to the folded form? (c) In the native form, the molecule has four \(-\mathrm{S}-\mathrm{S}-\) bonds that bridge parts of the chain. What effect do you predict these four linkages to have on the free energy and entropy of the native form relative to the free energy and entropy of a hypothetical folded structure that does not have any \(-\mathrm{S}-\mathrm{S}-\) linkages? Explain. (d) A gentle reducing agent converts the four \(-\mathrm{S}-\mathrm{S}-\) linkages in ribonuclease \(\mathrm{A}\) to eight \(-\mathrm{S}-\mathrm{H}\) bonds. What effect do you predict this conversion to have on the tertiary structure and entropy of the protein? (e) Which amino acid must be present for \(-\mathrm{SH}\) bonds to exist in ribonuclease A?

Adenine and guanine are members of a class of molecules known as purines; they have two rings in their structure. Thymine and cytosine, on the other hand, are pyrimidines,and have only one ring in their structure. Predict which have larger dispersion forces in aqueous solution, the purines or the pyrimidines.

Indicate whether each statement is true or false: (a) Disaccharides are a type of carbohydrate. (b) Sucrose is a monosaccharide. (c) All carbohydrates have the formula \(\mathrm{C}_{n} \mathrm{H}_{2 m} \mathrm{O}_{m} .\)
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

Organic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Kinetics

Read Explanation

The Earths Atmosphere

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free