Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 24: Problem 26

Give the general formula for any cyclic alkene, that is, a cyclic hydrocarbon with one double bond.

Short Answer

Expert verified
The general formula for any cyclic alkene with one double bond is \(C_nH_{2n-2}\).

Step by step solution

01

Understand cyclic alkenes

A cyclic alkene is a hydrocarbon molecule with a ring structure, containing a double bond between two carbon atoms. Cyclic alkenes are unsaturated, meaning they have the ability to form more bonds with other atoms because of the presence of the double bond.
02

Identify hydrocarbon formula

A hydrocarbon is a compound that consists of only hydrogen and carbon atoms. The general formula of a hydrocarbon is C_nH_m, where n represents the number of carbon atoms and m represents the number of hydrogen atoms.
03

Determine general formula for cyclic alkene with one double bond

For a cyclic alkene with one double bond, we first need to determine the number of carbon atoms in the molecule. Each carbon atom in a cyclic alkene contributes two hydrogen atoms, except for the two carbon atoms with a double bond. These two carbon atoms, with the double bond, contribute one hydrogen atom each to the compound. To create a general formula, we can represent the number of carbon atoms by the variable n. For the hydrogen atoms in the molecule with no double bond, there are 2(n-2) hydrogen atoms, and for the hydrogen atoms in the two carbon atoms with a double bond, there are 2 hydrogen atoms. Adding these two terms together gives the total number of hydrogen atoms: 2(n-2) + 2.
04

Simplify general formula

Combining the expressions for carbon and hydrogen atoms from step 3, we obtain the general formula for a cyclic alkene with one double bond: C_nH_{2(n - 2) + 2} Simplifying the formula: C_nH_{2n - 4 + 2} C_nH_{2n - 2} So, the general formula for any cyclic alkene with one double bond is \(C_nH_{2n-2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Is 3 -chloro-3-methylhexane chiral?

Draw the three distinct geometric isomers of \(2,4\)-hexadiene.

An unknown organic compound is found on elemental analysis to contain 68.1\(\%\) carbon, 13.7\(\%\) hydrogen, and 18.2\(\%\) oxygen by mass. It is slightly soluble in water. Upon careful oxidation it is converted into a compound that behaves chemically like a ketone and contains 69.7\(\%\) carbon, 11.7\(\%\) hydrogen, and 18.6\(\%\) oxygen by mass. Indicate two or more reasonable structures for the unknown.

Monosaccharides can be categorized in terms of the number of carbon atoms (pentoses have five carbons and hexoses have six carbons) and according to whether they contain an aldehyde (aldo-prefix, as in aldopentose) or ketone group (keto-prefix, as in ketopentose). Classify glucose and fructose in this way.

\begin{equation}\begin{array}{l}{\text { (a) Is } \mathrm{C}_{4} \mathrm{H}_{6} \text { a saturated or unsaturated hydrocarbon? }} \\ {\text { (b) Are all alkynes unsaturated? }}\end{array}\end{equation}
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation

Organic Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Physical Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free