Write a balanced chemical equation for the reaction that occurs when (a) titanium metal reacts with \(\mathrm{O}_{2}(g) ;(\mathbf{b})\) silver(I)oxide decomposes into silver metal and oxygen gas when heated; (c) propanol, \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}(l)\) burns in air; (d) methyl tert- butyl ether, \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}(l),\) burns in air.

Short Answer

Expert verified
a) \( Ti(s) + \frac{1}{2}O_{2}(g) \rightarrow TiO_{2}(s) \) b) \( 2Ag_{2}O(s) \rightarrow 4Ag(s) + O_{2}(g) \) c) \( C_{3}H_{7}OH(l) + \frac{9}{2}O_{2}(g) \rightarrow 3CO_{2}(g) + 4H_{2}O(l) \) d) \( C_{5}H_{12}O(l) + \frac{11}{2}O_{2}(g) \rightarrow 5CO_{2}(g) + 6H_{2}O(l) \)

Step by step solution

01

Write the unbalanced chemical equation

To write the equation, simply write down the reactants and the products: Ti(s) + O2(g) -> TiO2(s) #a1) Balance the chemical equation
02

To balance the equation, adjust the stoichiometric coefficients (the numbers in front of each molecule) to equalize the number of atoms of each element on both sides: Ti(s) + \( \frac{1}{2} \)O2(g) -> TiO2(s) #b) Silver(I) oxide decomposes into silver metal and oxygen gas when heated

Write the unbalanced chemical equation
03

Identify the reactants and the products of the reaction: 2Ag2O(s) -> 2Ag(s) + O2(g) #b1) Balance the chemical equation

In this case, the equation is already balanced: 2Ag2O(s) -> 4Ag(s) + O2(g) #c) Propanol, C3H7OH, burns in air
04

Write the unbalanced chemical equation

Identify the reactants and the products of the reaction: C3H7OH(l) + O2(g) -> CO2(g) + H2O(l) #c1) Balance the chemical equation
05

Balance the equation by adjusting the stoichiometric coefficients: C3H7OH(l) + \( \frac{9}{2} \)O2(g) -> 3CO2(g) + 4H2O(l) #d) Methyl tert-butyl ether, C5H12O, burns in air

Write the unbalanced chemical equation
06

Identify the reactants and the products of the reaction: C5H12O(l) + O2(g) -> CO2(g) + H2O(l) #d1) Balance the chemical equation

Balance the equation by adjusting the stoichiometric coefficients: C5H12O(l) + \( \frac{11}{2} \)O2(g) -> 5CO2(g) + 6H2O(l)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reaction Stoichiometry
Understanding stoichiometry is essential for balancing chemical equations and predicting the quantities of substances consumed and produced in a chemical reaction. It involves the calculation of the relative quantities of reactants and products, often measured in moles, taking into account the conservation of mass and the coefficients provided in a balanced equation.

For example, in the reaction where titanium metal reacts with oxygen, stoichiometry is used to determine that one mole of titanium reacts with half a mole of oxygen to produce one mole of titanium dioxide. Stoichiometry not only ensures that the chemical equation adheres to the law of conservation of mass but also enables us to predict how much product can be formed from a given amount of reactant.
Decomposition Reactions
Decomposition reactions involve a single compound breaking down into two or more simpler substances, usually when energy, such as heat, is supplied. For instance, the decomposition of silver(I) oxide into silver metal and oxygen gas is a typical example often used in laboratory demonstrations.

This process requires careful balancing of the chemical equation to ensure that the atoms on the left side of the equation equal the atoms on the right side. In the silver(I) oxide example, the balanced equation shows that two formula units of silver(I) oxide decompose to produce four atoms of silver and one molecule of oxygen gas, signifying that the reaction preserves the mass and number of atoms involved.
Combustion Reactions
Combustion reactions are rapid chemical reactions that typically involve oxygen from the air and produce heat and light. A familiar example of a combustion reaction is the burning of fuels like propane. When combustion reactions occur, reactants like hydrocarbons and oxygen are converted into products like carbon dioxide and water.

Propanol burning in air is a specific case of a combustion reaction. The balanced chemical equation carefully accounts for all the carbon, hydrogen, and oxygen atoms, ensuring that the chemical equation is physically plausible. Stoichiometry plays a crucial role in determining the coefficient of oxygen necessary to completely burn propanol, resulting in the proper quantities of carbon dioxide and water.
Balancing Chemical Equations
The balancing of chemical equations is a skill that involves equalizing the number of atoms of each element present in the reactants and products. This is a fundamental practice in chemistry because it reflects the conservation of matter and provides the correct proportions of substances involved in the chemical reaction.

Consider the case of methyl tert-butyl ether burning in air. The balanced chemical equation ensures that each carbon, hydrogen, and oxygen atom is accounted for on both sides of the equation. The process generally involves adjusting the stoichiometric coefficients before the compounds, and it is often helpful to balance certain elements last, such as hydrogen and oxygen, due to their frequent occurrence in multiple compounds within the equation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Write "true" or "false" for each statement. (a) A mole of horses contain a mole of horse legs. (b) A mole of water has a mass of 18.0 \(\mathrm{g} .\) (c) The mass of 1 molecule of water is 18.0 \(\mathrm{g}\) (d) A mole of NaCl (s) contains 2 moles of ions.

The koala dines exclusively on eucalyptus leaves. Its digestive system detoxifies the eucalyptus oil, a poison to other animals. The chief constituent in eucalyptus oil is a substance called eucalyptol, which contains \(77.87 \% \mathrm{C}, 11.76 \% \mathrm{H},\) and the remainder O. (a) What is the empirical formula for this substance? (b) A mass spectrum of eucalyptol shows a peak at about 154 amu. What is the molecular formula of the substance?

The thermite reaction, $$ \mathrm{Fe}_{2} \mathrm{O}_{3}+\mathrm{Al} \rightarrow \mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{Fe} $$ produces so much heat that the Fe product melts. This reaction is used industrially to weld metal parts under water, where a torch cannot be employed. It is also a favorite chemical demonstration in the lecture hall (on a small scale). (a) Balance the chemical equation for the thermite reaction, and include the proper states of matter. (b) Calculate how many grams of aluminum are needed to completely react with 500.0 g of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in this reaction. (c) This reaction produces 852 kJ of heat per mole of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) reacted. How many grams of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) are needed to produce \(1.00 \times 10^{4} \mathrm{kJ}\) of heat? (d) If you performed the reverse reaction aluminum-oxide plus iron makes iron oxide plus aluminum-would that reaction have heat as a reactant or a product?

Determine the formula weights of each of the following compounds: (a) nittrous oxide, \(\mathrm{N}_{2} \mathrm{O}\) , known as laughing gas and used as an anesthetic in dentistry; (b) benzoic acid; \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\) a substance used as a food preservative; \((c) \mathrm{Mg}(\mathrm{OH})_{2},\) the active ingredient in milk of magnesia; (d) urea, \(\left(\mathrm{NH}_{2}\right)_{2} \mathrm{CO},\) a compound used as a nitrogen fertilizer; (e) isopentyl acetate, \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{C}_{5} \mathrm{H}_{11},\) responsible for the odor of bananas.

When hydrocarbons are burned in a limited amount of air, both CO and \(\mathrm{CO}_{2}\) form. When 0.450 g of a particular hydrocarbon was burned in air, 0.467 \(\mathrm{g}\) of \(\mathrm{CO}, 0.733 \mathrm{g}\) of \(\mathrm{CO}_{2},\) and 0.450 \(\mathrm{g}\) of \(\mathrm{H}_{2} \mathrm{O}\) were formed. (a) What is the empirical formula of the compound? (b) How many grams of O \(_{2}\) were used in the reaction? (c) How many grams would have been required for complete combustion?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free