Determine the empirical formulas of the compounds with the following compositions by mass: $$ \begin{array}{l}{\text { (a) } 55.3 \% \mathrm{K}, 14.6 \% \mathrm{P}, \text { and } 30.1 \% \mathrm{O}} \\ {\text { (b) } 24.5 \% \mathrm{Na}, 14.9 \% \mathrm{Si}, \text { and } 60.6 \% \mathrm{F}} \\ {\text { (c) } 62.1 \% \mathrm{C}, 5.21 \% \mathrm{H}, 12.1 \% \mathrm{N}, \text { and the remainder O }}\end{array} $$

Short Answer

Expert verified
The empirical formulas for the given compounds are: (a) KPO₄ (b) Na₂SiF₆ (c) C₅H₀.₄₀₇N¹.₀₂₂O₂.₀₃₃

Step by step solution

01

Convert percentage composition to mass

Assume that each compound has a total mass of 100 grams. This assumption allows us to easily convert the percentage composition directly into grams of each element. For example, For compound (a): - 55.3% K implies 55.3 grams of K - 14.6% P implies 14.6 grams of P - 30.1% O implies 30.1 grams of O We will make similar calculations for compounds (b) and (c).
02

Determine moles of each element

Next, we need to determine the moles of each element in the compound. To do this, divide the mass (in grams) of each element by its respective molar mass. For compound (a): - Moles of K: \(\frac{55.3}{39.10}\) (molar mass of K is 39.10 g/mol) - Moles of P: \(\frac{14.6}{30.97}\) (molar mass of P is 30.97 g/mol) - Moles of O: \(\frac{30.1}{16.00}\) (molar mass of O is 16.00 g/mol) Calculate the moles for elements in compounds (b) and (c) similarly.
03

Determine the mole ratio

To determine the mole ratio, divide all the moles calculated in Step 2 by the smallest moles value among the elements in that compound. For compound (a): - Calculate the smallest moles value: min(K, P, O) - Divide all the moles by the smallest moles value to get the mole ratio. Do this also for compounds (b) and (c).
04

Determine the empirical formula

Use the mole ratios obtained in Step 3 to construct the empirical formula for each compound. For compound (a): - Combine the elements with their respective ratios, rounding to the nearest whole number if the ratios are close to integers. Perform this step for compounds (b) and (c), and the empirical formulas will be determined.

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Most popular questions from this chapter

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.50 \(\mathrm{g}\) of sodium carbonate is mixed with one containing 5.00 \(\mathrm{g}\) of silver nitrate. How many grams of sodium carbonate, silver nitrate, silver carbonate, and sodium nitrate are present after the reaction is complete?

A mixture containing \(\mathrm{KClO}_{3}, \mathrm{K}_{2} \mathrm{CO}_{3}, \mathrm{KHCO}_{3},\) and \(\mathrm{KCl}\) was heated, producing \(\mathrm{CO}_{2}, \mathrm{O}_{2},\) and \(\mathrm{H}_{2} \mathrm{O}\) gases according to the following equations: $$ \begin{array}{l}{2 \mathrm{KClO}_{3}(s) \longrightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g)} \\ {2 \mathrm{KHCO}_{3}(s) \longrightarrow \mathrm{K}_{2} \mathrm{O}(s)+\mathrm{H}_{2} \mathrm{O}(g)+2 \mathrm{CO}_{2}(g)} \\\ {\mathrm{K}_{2} \mathrm{CO}_{3}(s) \longrightarrow \mathrm{K}_{2} \mathrm{O}(s)+\mathrm{CO}_{2}(g)}\end{array} $$ The KCl does not react under the conditions of the reaction. If 100.0 g of the mixture produces 1.80 \(\mathrm{g}\) of \(\mathrm{H}_{2} \mathrm{O}, 13.20 \mathrm{g}\) of \(\mathrm{CO}_{2}\) and 4.00 \(\mathrm{g}\) of \(\mathrm{O}_{2},\) what was the composition of the original mixture? (Assume complete decomposition of the mixture.)

Calculate the percentage by mass of the indicated element in the following compounds: \((\mathbf{a})\) carbon in acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2}, \mathrm{a}\) gas used in welding; \((\mathbf{b} )\) hydrogen in ascorbic acid, \(\mathrm{HC}_{6} \mathrm{H}_{7} \mathrm{O}_{6}\) also known as vitamin \(\mathrm{C} ;(\mathbf{c})\) hydrogen in ammonium sulfate, \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4},\) a substance used as a nitrogen fertilizer; \((\mathbf{d})\) platinum in \(\mathrm{PtCl}_{2}\left(\mathrm{NH}_{3}\right)_{2},\) a chemotherapy agent called cisplatin; \((\mathbf{e})\) oxygen in the female sex hormone estradiol, \(\mathrm{C}_{18} \mathrm{H}_{24} \mathrm{O}_{2} ;(\mathbf{f})\) carbon in capsaicin, \(\mathrm{C}_{18} \mathrm{H}_{27} \mathrm{NO}_{3},\) the compound that gives the hot taste to chili peppers.

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of \(\mathrm{NH}_{3}\) to \(\mathrm{NO} :\) $$ 4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) $$ In a certain experiment, 2.00 \(\mathrm{g}\) of \(\mathrm{NH}_{3}\) reacts with 2.50 \(\mathrm{g}\) of \(\mathrm{O}_{2} .\) (a) Which is the limiting reactant? (b) How many grams of \(\mathrm{NO}\) and \(\mathrm{H}_{2} \mathrm{O}\) form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed? (d) Show that your calculations in parts (b) and (c) are consistent with the law of conservation of mass.

A compound, \(\mathrm{KBrO}_{x},\) where \(x\) is unknown, is analyzed and found to contain 52.92\(\%\) Br. What is the value of \(x ?\)

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