Write "true" or "false" for each statement. (a) We balance chemical equations as we do because energy must be conserved. (b) If the reaction 2 \(\mathrm{O}_{3}(g) \rightarrow 3 \mathrm{O}_{2}(g)\) goes to completion and all \(\mathrm{O}_{3}\) is converted to \(\mathrm{O}_{2},\) then the mass of \(\mathrm{O}_{3}\) at the beginning of the reaction must be the same as the mass of \(\mathrm{O}_{2}\) at the end of the reaction. (c) You can balance the "water-splitting" reaction \(\mathrm{H}_{2} \mathrm{O}(I) \rightarrow \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\) by writing it this way: \(\mathrm{H}_{2} \mathrm{O}_{2}(l) \rightarrow \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\)

Short Answer

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\( \textbf{False, True, False} \)

Step by step solution

01

Statement (a) - Balancing Chemical Equations and Energy Conservation

We balance chemical equations to ensure that the number of atoms of each element remains the same on both the reactant and product side. This is in line with the law of conservation of mass, which states that mass cannot be created nor destroyed in chemical reactions. So, the reason we balance chemical equations is not directly related to the conservation of energy but the conservation of mass. Therefore, the statement is: \( \boxed{\textbf{False}} \)
02

Statement (b) - Comparison of Masses before and after the Reaction

Given the balanced chemical equation: \( 2\,\mathrm{O}_{3}(g) \rightarrow 3\,\mathrm{O}_{2}(g) \) This equation tells us that every two molecules of ozone (\(\mathrm{O}_{3}\)), upon going to completion, are converted into three molecules of molecular oxygen (\(\mathrm{O}_{2}\)). According to the law of conservation of mass, the mass of the reactants should be equal to the mass of the products. Given the stoichiometry of the reaction, the conservation of mass should hold true. Hence, the statement is: \( \boxed{\textbf{True}} \)
03

Statement (c) - Balancing the Water-Splitting Reaction

The given water-splitting reaction reads: \( \mathrm{H}_{2}\,\mathrm{O}(l) \rightarrow \mathrm{H}_{2}(g) + \mathrm{O}_{2}(g) \) This reaction is not balanced as written, as there are only two hydrogen atoms and one oxygen atom on the reactant side, while there are two oxygen atoms in the product \(\mathrm{O}_{2}(g)\). To balance the equation, we can adjust the coefficients as follows: \( 2\, \mathrm{H}_{2}\,\mathrm{O}(l) \rightarrow 2\, \mathrm{H}_{2}(g) + \mathrm{O}_{2}(g) \) The suggested balanced equation: \( \mathrm{H}_{2}\,\mathrm{O}_{2}(l) \rightarrow \mathrm{H}_{2}(g) + \mathrm{O}_{2}(g) \) is incorrect as it introduces a new molecule (hydrogen peroxide) that is not involved in the actual reaction, creating a mismatch in terms of the structural and stoichiometric properties of the balanced equation. Thus, the statement is: \( \boxed{\textbf{False}} \)

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Most popular questions from this chapter

Determine the formula weights of each of the following compounds: (a) nitric acid, HNO \(_{3} ;\) (b) \(\mathrm{KMnO}_{4} ;\) (c) \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) (d) quartz, SiO \(_{2} ;\) (e) gallium sulfide, (f) chromium(III) sulfate, (g) phosphorus trichloride.

Balance the following equations: $$ \begin{array}{l}{\text { (a) } \mathrm{CO}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)} \\ {\text { (b) } \mathrm{N}_{2} \mathrm{O}_{5}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{HNO}_{3}(a q)} \\ {\text { (c) } \mathrm{CH}_{4}(g)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{CCl}_{4}(l)+\mathrm{HCl}(g)} \\ {\text { (d) } \mathrm{Zn}(\mathrm{OH})_{2}(s)+\mathrm{HNO}_{3}(a q) \longrightarrow \mathrm{Zn}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{H}_{2} \mathrm{O}(l)}\end{array} $$

Hydrofluoric acid, HF(aq), cannot be stored in glass bottles because compounds called silicates in the glass are attacked by the HF(aq). Sodium silicate (Na \(_{2} \mathrm{SiO}_{3} ),\) for example, reacts as follows: $$ \mathrm{Na}_{2} \mathrm{SiO}_{3}(s)+8 \mathrm{HF}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{SiF}_{6}(a q)+2 \operatorname{NaF}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l) $$ (a) How many moles of HF are needed to react with 0.300 mol of \(\mathrm{Na}_{2} \mathrm{SiO}_{3} ?\) (b) How many grams of NaF form when 0.500 mol of HF reacts with excess \(\mathrm{Na}_{2} \mathrm{SiO}_{3} ?\) (c) How many grams of \(\mathrm{Na}_{2} \mathrm{SiO}_{3}\) can react with 0.800 g of HF?

The combustion of one mole of liquid ethanol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) , produces 1367 \(\mathrm{kJ}\) of heat. Calculate how much heat is produced when 235.0 \(\mathrm{g}\) of ethanol are combusted.

A chemical plant uses electrical energy to decompose aqueous solutions of NaCl to give \(\mathrm{Cl}_{2}, \mathrm{H}_{2},\) and \(\mathrm{NaOH} :\) $$ 2 \mathrm{NaCl}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NaOH}(a q)+\mathrm{H}_{2}(g)+\mathrm{Cl}_{2}(g) $$ If the plant produces \(1.5 \times 10^{6} \mathrm{kg}\left(1500\) metric tons) of \(\mathrm{Cl}_{2}\right.\) daily, estimate the quantities of \(\mathrm{H}_{2}\) and \(\mathrm{NaOH}\) produced.

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