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Chapter 4: Problem 44

As \(\mathrm{K}_{2} \mathrm{O}\) dissolves in water, the oxide ion reacts with water molecules to form hydroxide ions. (a) Write the molecular and net ionic equations for this reaction. (b) Based on the definitions of acid and base, what ion is the base in this reaction? (c) What is the acid in the reaction? (d) What is the spectator ion in the reaction?

Short Answer

Expert verified
a) The molecular and net ionic equations are: \[K_2O + H_2O \rightarrow 2KOH\] \[K_2O + H_2O \rightarrow 2K^+ + 2OH^-\] b) The base in this reaction is the oxide ion (O^2-). c) The acid in the reaction is water (H2O). d) There is no spectator ion in this reaction.

Step by step solution

01

Write the balanced molecular equation

First, we need to begin by writing the overall balanced molecular equation for the reaction between K2O and water. K2O reacts with water to form KOH: \[K_2O + H_2O \rightarrow 2KOH\]
02

Write the balanced ionic equation for the reaction

Next, we will dissociate the strong electrolytes into their respective ions. In this case, KOH is a strong base and will completely dissociate into its ions: \[2K^+ + 2OH^-\] Since K2O is not dissolved in the solution, we will leave it in its molecular form. Water, similarly, will stay in its molecular form as well. So, the balanced ionic equation will look like this: \[K_2O + H_2O \rightarrow 2K^+ + 2OH^-\]
03

Write the net ionic equation for the reaction

Now, let's eliminate the species that are common to both sides of the balanced ionic equation (spectator ions). In this case, there is no common species to eliminate. Therefore, the net ionic equation will be the same as the balanced ionic equation: \[K_2O + H_2O \rightarrow 2K^+ + 2OH^-\]
04

Identify the base in the reaction

The base in the reaction is the species that accepts a proton (H+ ion) from the acid. In this case, the oxide ion (O^2-) coming from K2O is the base, as it combines with water to form 2 hydroxide ions: \[O^{2-} + H_2O \rightarrow 2OH^-\]
05

Identify the acid in the reaction

The acid in the reaction is the species that donates the proton (H+ ion) to the base. In this case, water is the acid as it is the source of the protons needed to form 2 hydroxide ions: \[O^{2-} + H_2O \rightarrow 2OH^-\]
06

Identify the spectator ion in the reaction

Spectator ions are the species that don't participate in the reaction. In this case, there are no spectator ions as all species are involved in the chemical change. K2O and water react to form KOH, and all the species undergo a transformation during the reaction. To summarize: a) The molecular and net ionic equations are: \[K_2O + H_2O \rightarrow 2KOH\] \[K_2O + H_2O \rightarrow 2K^+ + 2OH^-\] b) The base in this reaction is the oxide ion (O^2-). c) The acid in the reaction is water (H2O). d) There is no spectator ion in this reaction.

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Most popular questions from this chapter

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