An 8.65 -g sample of an unknown group 2 A metal hydroxide is dissolved in 85.0 \(\mathrm{mL}\) of water. An acid-base indicator is added and the resulting solution is titrated with 2.50 \(\mathrm{M}\) \(\mathrm{HCl}(a q)\) solution. The indicator changes color, signaling that the equivalence point has been reached, after 56.9 \(\mathrm{mL}\) of the hydrochloric acid solution has been added. (a) What is the molar mass of the metal hydroxide? (b) What is the identity of the metal cation: \(\mathrm{Ca}^{2+}, \mathrm{Sr}^{2+},\) or \(\mathrm{Ba}^{2+?}\) ?

Short Answer

Expert verified
Based on the provided step-by-step solution, the short answer to the question is as follows. (a) To find the molar mass of the metal hydroxide, first, calculate the moles of HCl used in the titration: \(Moles_{HCl} = 2.50 M * 0.0569 L\) Next, use stoichiometry to find the moles of metal hydroxide (MH): \(Moles_{MH} = \frac{Moles_{HCl}}{2}\) Then, calculate the molar mass of the metal hydroxide: \(Molar\,mass_{MH} = \frac{8.65 g}{Moles_{MH}}\) (b) To identify the metal cation, compare the calculated molar mass with the known molar masses of Group 2A metal hydroxides (Ca(OH)2, Sr(OH)2, and Ba(OH)2) to find the metal hydroxide with the closest molar mass. This will determine the identity of the metal cation (Ca2+, Sr2+, or Ba2+).

Step by step solution

01

Calculate the moles of HCl used in the titration

First, determine the moles of HCl that was used in the titration. We have the volume (56.9 mL) and molarity (2.50 M) of the HCl solution. Moles can be calculated using the formula: Moles of HCl = Molarity * Volume (in liters) \(Moles_{HCl} = 2.50 M * 0.0569 L\)
02

Use stoichiometry to obtain the moles of the metal hydroxide

Since we know the moles of HCl, we can now use stoichiometry to find the moles of metal hydroxide (denoted as MH here) because at the equivalence point, the moles of MH in the original solution should be equal to the moles of HCl used in titration. The balanced chemical equation would look something like this: \(MH + 2 HCl -> MCl_2 + 2 H_2O\) Here, the stoichiometric ratio of the metal hydroxide to the HCl is 1:2 (as shown in the balanced equation). Therefore, to find the moles of metal hydroxide: \(Moles_{MH} = \frac{Moles_{HCl}}{2}\)
03

Calculate the mass of the metal hydroxide

Now that we have the moles of metal hydroxide, we can find the mass of the metal hydroxide from the given sample mass (8.65 g). To do this, we use the formula: \(g_{MH} = Moles_{MH} * Molar\,mass_{MH}\) Here, we need to solve for the molar mass of the metal hydroxide (Molar mass of MH).
04

Determine the molar mass of the metal hydroxide

Rearrange the formula from Step 3 to solve for the molar mass of the metal hydroxide: \(Molar\,mass_{MH} = \frac{g_{MH}}{Moles_{MH}}\) This will give us the molar mass of the metal hydroxide.
05

Identify the metal cation

Now that we have the molar mass of the metal hydroxide, we can compare it with known molar masses of group 2A metal hydroxides (Ca(OH)2, Sr(OH)2, and Ba(OH)2) to identify the metal cation (Ca2+, Sr2+, or Ba2+). Compare the molar mass calculated in Step 4 with the molar masses of known metal hydroxides, and find the metal hydroxide with the closest molar mass. This will give us the identity of the metal cation.

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