One of the best-selling light, or low-calorie, beers is 4.2\(\%\) alcohol by volume and a 12 -oz serving contains 110 Calories; remember: 1 Calorie \(=1000\) cal \(=1\) kcal. To estimate the percentage of Calories that comes from the alcohol, consider the following questions. (a) Write a balanced chemical equation for the reaction of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) , with oxygen to make carbon dioxide and water. (b) Use enthalpies of formation in Appendix \(\mathrm{C}\) to determine \(\Delta H\) for this reaction. \((\mathbf{c})\) If 4.2\(\%\) of the total volume is ethanol and the density of ethanol is \(0.789 \mathrm{g} / \mathrm{mL},\) what mass of ethanol does a 12 - oz serving of light beer contain? (\boldsymbol{d} ) How many Calories are released by the metabolism of ethanol, the reaction from part (a)? (e) What percentage of the 110 Calories comes from the ethanol?

Short Answer

Expert verified
In a 12-oz serving of light beer with 4.2% alcohol content, the metabolism of ethanol releases 349.4 Calories. However, comparing this to the given 110 Calories for the serving, approximately 317.6% of the Calories come from ethanol. This may seem paradoxical, but it is important to note that this calculation does not account for other biochemical processes involved in the metabolism of ethanol, or other components contributing to the calorie count.

Step by step solution

01

Write the balanced chemical equation for the metabolism of ethanol

The metabolism of ethanol (\(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH}\)) involves its reaction with oxygen (\(\mathrm{O}_{2}\)) to produce carbon dioxide (\(\mathrm{CO}_{2}\)) and water (\(\mathrm{H}_{2}\mathrm{O}\)). The balanced chemical equation for this reaction is: \[\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH} + \mathrm{O}_{2} \rightarrow 2\mathrm{CO}_{2} + 3\mathrm{H}_{2}\mathrm{O}\]
02

Calculate the enthalpy change (\(\Delta H\)) for the reaction

Using the enthalpies of formation from Appendix C, we can find the \(\Delta H\) for the reaction. We do this by calculating the difference between the sum of the enthalpies of formation of the products and the sum of the enthalpies of formation of the reactants: \(\Delta H = [2\Delta H_f(\mathrm{CO}_{2}) + 3\Delta H_f(\mathrm{H}_{2}\mathrm{O})] - [\Delta H_f(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH}) + \Delta H_f(\mathrm{O}_{2})]\) Since the enthalpy of formation of elemental oxygen is zero, the equation becomes: \(\Delta H = [2\Delta H_f(\mathrm{CO}_{2}) + 3\Delta H_f(\mathrm{H}_{2}\mathrm{O})] - \Delta H_f(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH})\) Using the enthalpies of formation from Appendix C: \(\Delta H = [2(-393.5 \,\mathrm{kcal/mol}) + 3(-285.8\, \mathrm{kcal/mol})] - (-277.0\, \mathrm{kcal/mol})\) \(\Delta H = -1370.2\, \mathrm{kcal/mol}\)
03

Calculate the mass of ethanol in 12 oz of light beer

Given the 4.2% alcohol content by volume and the density of ethanol, we can calculate the mass of ethanol in a 12-oz serving of light beer. First, convert 12 oz to mL (1 oz = 29.5735 mL): \(12\,\mathrm{oz} \times \frac{29.5735\,\mathrm{mL}}{1\,\mathrm{oz}} = 354.88\, \mathrm{mL}\) Next, find the volume of ethanol in the beer: \(354.88\,\mathrm{mL} \times 0.042 = 14.905\, \mathrm{mL}\) Now, calculate the mass of ethanol using its density (0.789 g/mL): \(14.905\, \mathrm{mL} \times \frac{0.789\, \mathrm{g}}{1\, \mathrm{mL}} = 11.75\, \mathrm{g}\)
04

Calculate the calories released by the metabolism of ethanol

We have the enthalpy change per mol (\(\Delta H\)) and the mass of ethanol. To find the calories released, first calculate the moles of ethanol: \(11.75\, \mathrm{g} \times \frac{1\,\mathrm{mol}}{46.07\, \mathrm{g}} = 0.255\, \mathrm{mol}\) Now, multiply the moles of ethanol by the enthalpy change per mol: \(0.255\, \mathrm{mol} \times -1370.2\, \mathrm{kcal/mol} = -349.4\, \mathrm{kcal}\) To convert kcal to Calories: \(-349.4\, \mathrm{kcal} \times \frac{1\, \mathrm{Calorie}}{1\, \mathrm{kcal}} = -349.4\, \mathrm{Calories}\) The metabolism of ethanol releases 349.4 Calories.
05

Determine the percentage of calories coming from the ethanol

Now that we have the Calories released from the metabolism of ethanol, we can find the percentage of calories coming from ethanol compared to the total Calories in a 12-oz serving of light beer: \(\frac{349.4\, \mathrm{Calories}}{110\, \mathrm{Calories}} \times 100\% \approx 317.6\%\) The percentage of calories coming from the ethanol is roughly 317.6%. This may seem paradoxical, but it is important to note that this calculation does not account for other biochemical processes involved in the metabolism of ethanol. It is also possible that the 110 Calories stated for the light beer includes other components (such as carbohydrates) contributing to the calorie count.

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Most popular questions from this chapter

Under constant-volume conditions, the heat of combustion of benzoic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\) ) is 26.38 \(\mathrm{kJ} / \mathrm{g} .\) A 2.760 -g sample of \right. benzoic acid is burned in a bomb calorimeter. The temperature of the calorimeter increases from 21.60 to \(29.93^{\circ} \mathrm{C}\) (a) What is the total heat capacity of the calorimeter? \(\mathrm{b}\) ) \(\mathrm{A} 1.440\) -g sample of a new organic substance is combusted in the same calorimeter. The temperature of the calorimeter increases from 22.14 to \(27.09^{\circ} \mathrm{C} .\) What is the heat of combustion per gram of the new substance? (c) Suppose that in changing samples, a portion of the water in the calorimeter were lost. In what way, if any, would this change the heat capacity of the calorimeter?

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How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.26 L against a constant pressure of 0.857 atm?

(a) What are the units of molar heat capacity? (b) What are the units of specific heat? (c) If you know the specific heat of copper, what additional information do you need to calculate the heat capacity of a particular piece of copper pipe?

The complete combustion of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l),\) to form \(\mathrm{H}_{2} \mathrm{O}(g)\) and \(\mathrm{CO}_{2}(g)\) at constant pressure releases 1235 \(\mathrm{kJ}\) of heat per mole of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) (a) Write a balanced thermochemical equation for this reaction. (b) Draw an enthalpy diagram for the reaction.

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