A magnesium ion, Mg \(^{2+},\) with a charge of \(3.2 \times 10^{-19} \mathrm{Cand}\) an oxide ion, \(\mathrm{O}^{2-},\) with a charge of \(-3.2 \times 10^{-19} \mathrm{C}\) , are separated by a distance of 0.35 \(\mathrm{nm}\) . How much work would be required to increase the separation of the two ions to an infinite distance?

Short Answer

Expert verified
To separate a magnesium ion (Mg\(^{2+}\)) and an oxide ion (O\(^{2-}\)) from a distance of \(0.35 \,\text{nm}\) to an infinite distance, we need to do work equal to the potential energy but with the opposite sign. Using the given charges and the potential energy formula, we calculate the potential energy as \(-3.264 \times 10^{-18} \,\text{J}\). Therefore, the work required to separate the ions is \(3.264 \times 10^{-18}\) Joules.

Step by step solution

01

Understand the problem and identify the given values

We are given the following information: - Charge of magnesium ion (Mg\(^{2+}\)): \(Q_1 = 3.2 \times 10^{-19} \,\text{C}\) - Charge of oxide ion (O\(^{2-}\)): \(Q_2 = -3.2 \times 10^{-19} \,\text{C}\) - Distance between the ions: \(r = 0.35 \,\text{nm}\) (convert it to meters) - The work required to increase the separation of the two ions to an infinite distance.
02

Convert the distance from nm to meters

To use the SI units in our calculation, we need to convert the distance of separation (\(r\)) from nm to meters: $$ r = 0.35 \,\mathrm{nm} \times \frac{1 \times 10^{-9} \,\mathrm{m}}{1 \,\mathrm{nm}} = 3.5 \times 10^{-10} \,\text{m} $$
03

Use the potential energy formula

We will calculate the potential energy \(U\) between the two charged particles (ions) using the following formula: $$ U = k \frac{Q_1 \times Q_2}{r} $$ where \(k\) (the Coulomb constant) is \(8.98755 \times 10^9 \mathrm{Nm^2/C^2}\), \(Q_1\) and \(Q_2\) are the charges, and \(r\) is the separation distance.
04

Calculate the potential energy

Now, substitute the given values into the formula to calculate the potential energy between the two ions: $$ U = (8.98755 \times 10^9 \,\mathrm{Nm^2/C^2}) \times \frac{(3.2 \times 10^{-19}\,\text{C}) \times (-3.2 \times 10^{-19} \,\text{C})}{3.5 \times 10^{-10} \,\text{m}} $$ Calculating the value, we get: $$ U = -3.264 \times 10^{-18} \,\text{J} $$
05

Calculate the work required

To separate the two ions to an infinite distance, we need to do work equal to the potential energy but with the opposite sign (as potential energy at infinite distance is zero). Hence, the work required \(W\) to separate them is: $$ W = -U = 3.264 \times 10^{-18} \,\text{J} $$ Therefore, the work required to increase the separation of the two ions to an infinite distance is \(3.264 \times 10^{-18}\) Joules.

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