During a normal breath, our lungs expand about 0.50 L against an external pressure of 1.0 atm. How much work is involved in this process (in J)?

Short Answer

Expert verified
The work involved in this process is approximately -50.66 J (in Joules).

Step by step solution

01

Convert volume to SI units

We are given the volume expansion in liters (L) and need to convert it to cubic meters (m³) which is the SI unit for volume. To do so, we will use the conversion factor: 1 L = 0.001 m³ \newline \(\Delta V\) = 0.50 L \newline \(0.50 L \times \frac{0.001 m³}{1 L} \) \newline \(\Delta V = 0.0005 m³\)
02

Convert pressure to SI units

We are given the pressure in atmospheres (atm) and need to convert it to pascals (Pa) which is the SI unit for pressure. To do so, we will use the conversion factor: 1 atm = 101325 Pa \newline \(P =\) 1.0 atm \newline \(1.0 atm \times \frac{101325 Pa}{1 atm}\) \newline \(P = 101325 Pa\)
03

Calculate the work done

Now that we have the volume and pressure in SI units, we can apply the formula for calculating the work done against a constant external pressure: \newline \(W = -P \Delta V\) \newline Substituting the values, we get: \newline \(W = -(101325 Pa)(0.0005 m³)\) \newline \(W = -50.6625 J\) Since the work done is negative, it means that the work is done by the body to expand the lungs. Therefore, the work involved in this process is approximately -50.66 J (in Joules).

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