Among the elementary subatomic particles of physics is the muon, which decays within a few microseconds after formation. The muon has a rest mass 206.8 times that of an electron. Calculate the de Broglie wavelength associated with a muon traveling at \(8.85 \times 10^{5} \mathrm{cm} / \mathrm{s}\) .

Short Answer

Expert verified
The de Broglie wavelength associated with a muon traveling at \(8.85 \times 10^{5} \mathrm{cm} / \mathrm{s}\) is calculated as \(λ = \dfrac{6.626 \times 10^{-27}}{206.8 \times (9.11 \times 10^{-28}) \times (8.85 \times 10^5)} \) cm.

Step by step solution

01

Calculate the mass of the muon

Given that the muon has a rest mass 206.8 times that of an electron, we will calculate the mass of the muon by multiplying the mass of an electron by this factor. Mass of electron, \(m_e = 9.11 \times 10^{-28}\) g Mass of muon, \(m_\mu = 206.8 \times m_e = 206.8 \times (9.11 \times 10^{-28})\) g
02

Calculate the momentum of the muon

Using the formula for momentum \(p = mv\) and the given velocity \(v = 8.85 \times 10^5 \) cm/s, we will calculate the momentum: \(p = m_\mu v = 206.8 \times (9.11 \times 10^{-28}) \times (8.85 \times 10^5) \) g cm/s
03

Calculate the de Broglie wavelength

Now that we have the momentum of the muon, we can use the de Broglie wavelength formula to calculate the wavelength: \(λ = \dfrac{h}{p}\), Where Planck's constant, \(h = 6.626 \times 10^{-27} \) erg s. \(λ = \dfrac{6.626 \times 10^{-27}}{206.8 \times (9.11 \times 10^{-28}) \times (8.85 \times 10^5)} \) cm Now that we have all the values plugged in, we can compute the de Broglie wavelength of the muon traveling at \(8.85 \times 10^5 \mathrm{cm} / \mathrm{s} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine which of the following statements are false and correct them. (a) The frequency of radiation increases as the wavelength increases. (b) Electromagnetic radiation travels through a vacuum at a constant speed, regardless of wavelength. (c) Infrared light has higher frequencies than visible light. (d) The glow from a fireplace, the energy within a microwave oven, and a foghorn blast are all forms of electromagnetic radiation.

Consider a fictitious one-dimensional system with one electron. The wave function for the electron, drawn below, is \(\psi(x)=\sin x\) from \(x=0\) to \(x=2 \pi\) . (a) Sketch the probability density, \(\psi^{2}(x),\) from \(x=0\) to \(x=2 \pi .(\mathbf{b})\) At value or values of \(x\) will there be the greatest probability of finding the electron? (c) What is the probability that the electron will be found at \(x=\pi ?\) What is such a point in a wave function called? [Section 6.5\(]\)

Using Heisenberg's uncertainty principle, calculate the uncertainty in the position of (a) a 1.50-mg mosquito moving at a speed of 1.40 \(\mathrm{m} / \mathrm{s}\) if the speed is known to within \(\pm 0.01 \mathrm{m} / \mathrm{s}\) ; (b) a proton moving at a speed of \((5.00 \pm 0.01) \times 10^{4} \mathrm{m} / \mathrm{s}\) . (The mass of a proton is given in the table of fundamental constants in the inside cover of the text.)

For orbitals that are symmetric but not spherical, the contour representations (as in Figures 6.23 and 6.24 ) suggest where nodal planes exist (that is, where the electron density is zero). For example, the \(p_{x}\) orbital has a node wherever \(x=0\) . This equation is satisfied by all points on the \(y z\) plane, so this plane is called a nodal plane of the \(p_{x}\) orbital. (a) Determine the nodal plane of the \(p_{z}\) orbital. (b) What are the two nodal planes of the \(d_{x y}\) orbital? (c) What are the two nodal planes of the \(d_{x^{2}-y^{2}}\) orbital?

(a) A green laser pointer emits light with a wavelength of 532 nm. What is the frequency of this light? (b) What is the energy of one of these photons? (c) The laser pointer emits light because electrons in the material are excited (by a battery) from their ground state to an upper excited state. When the electrons return to the ground state, they lose the excess energy in the form of 532 -nm photons. What is the energy gap between the ground state and excited state in the laser material?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free