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Chapter 6: Problem 71

What is the maximum number of electrons that can occupy each of the following subshells? (a) 3p, (b) \(5 d,(\mathbf{c}) 2 s,(\mathbf{d}) 4 f .\)

Short Answer

Expert verified
The maximum number of electrons that can occupy the given subshells are: (a) 3p: \(6\) electrons, (b) 5d: \(10\) electrons, (c) 2s: \(2\) electrons, and (d) 4f: \(14\) electrons.

Step by step solution

01

Determine the angular quantum number (ℓ) for each subshell

For each subshell given, determine the angular quantum number (ℓ) corresponding to the subshell type (s=0, p=1, d=2, f=3): (a) 3p - ℓ=1 (p subshell) (b) 5d - ℓ=2 (d subshell) (c) 2s - ℓ=0 (s subshell) (d) 4f - ℓ=3 (f subshell)
02

Apply the 2(2ℓ + 1) formula for each subshell

Now that we have the angular quantum numbers for each subshell, we will use the formula 2(2ℓ+1) to find the maximum number of electrons that can occupy each given subshell. (a) For 3p: Maximum number of electrons = 2(2(1) + 1) = 2(2+1) = 2(3) = 6 (b) For 5d: Maximum number of electrons = 2(2(2) + 1) = 2(4+1) = 2(5) = 10 (c) For 2s: Maximum number of electrons = 2(2(0) + 1) = 2(0+1) = 2(1) = 2 (d) For 4f: Maximum number of electrons = 2(2(3) + 1) = 2(6+1) = 2(7) = 14
03

Write the final answer

The maximum number of electrons that can occupy each of the given subshells are: (a) 3p: 6 electrons (b) 5d: 10 electrons (c) 2s: 2 electrons (d) 4f: 14 electrons

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Most popular questions from this chapter

Label each of the following statements as true or false. For those that are false, correct the statement. (a) Visible light is a form of electromagnetic radiation. (b) Ultraviolet light has longer wavelengths than visible light. (c) \(X\) rays travel faster than microwaves. (d) Electromagnetic radiation and sound waves travel at the same speed.

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