Chapter 6: Problem 72
What is the maximum number of electrons in an atom that can have the following quantum numbers? (a) \(n=3, m_{l}=-2 ;(\mathbf{b}) n=4, l=3 ;(\mathbf{c}) n=5, l=3, m_{l}=2\) (d) \(n=4, l=1, m_{l}=0\)
Chapter 6: Problem 72
What is the maximum number of electrons in an atom that can have the following quantum numbers? (a) \(n=3, m_{l}=-2 ;(\mathbf{b}) n=4, l=3 ;(\mathbf{c}) n=5, l=3, m_{l}=2\) (d) \(n=4, l=1, m_{l}=0\)
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Get started for freeSketch the shape and orientation of the following types of orbitals: (a) \(p_{x},(\mathbf{b}) d_{2}^{2},(\mathbf{c}) d_{x^{2}-y^{2}}\)
Neutron diffraction is an important technique for determining the structures of molecules. Calculate the velocity of a neutron needed to achieve a wavelength of 1.25 A. (Refer to the inside cover for the mass of the neutron.)
State where in the periodic table these elements appear: $$ \begin{array}{l}{\text { (a) elements with the valence-shell electron configuration }} \\ {n s^{2} n p^{5}} \\ {\text { (b) elements that have three unpaired p electrons }} \\ {\text { (c) an element whose valence electrons are } 4 s^{2} 4 p^{1}} \\ {\text { (d) the } d \text { -block elements [ Section } 6.9 ]}\end{array} $$
The energy from radiation can be used to cause the rupture of chemical bonds. A minimum energy of 242 \(\mathrm{kJ} / \mathrm{mol}\) is required to break the chlorine-chlorine bond in \(\mathrm{Cl}_{2} .\) What is the longest wavelength of radiation that possesses the necessary energy to break the bond? What type of electromagnetic radiation is this?
An electron is accelerated through an electric potential to a kinetic energy of \(2.15 \times 10^{-15} \mathrm{J}\) . What is its characteristic wavelength? [Hint: Recall that the kinetic energy of a moving object is \(E=\frac{1}{2} m v^{2},\) where \(m\) is the mass of the object and \(\nu\) is the speed of the object.
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