Write the electron configurations for the following ions, and determine which have noble-gas configurations: \((\mathbf{a})\mathrm{Ru}^{3+}\) \((\mathbf{b}) \mathrm{As}^{3-},(\mathbf{c}) \mathrm{Y}^{3+},(\mathbf{d}) \mathrm{Pd}^{2+},(\mathbf{e}) \mathrm{Pb}^{2+},(\mathbf{f}) \mathrm{Au}^{3+}.\)

Short Answer

Expert verified
The electron configurations for the given ions are as follows: (a) \(Ru^{3+}\): \(1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{7}\) - not a noble gas configuration (b) \(As^{3-}\): \(1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6\) - matches Kr (noble gas configuration) (c) \(Y^{3+}\): \(1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6\) - matches Kr (noble gas configuration) (d) \(Pd^{2+}\): \(1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{8}\) - not a noble gas configuration (e) \(Pb^{2+}\): \(1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{10} \ 4f^{14} \ 5s^2 \ 5p^6 \ 5d^{10} \ 6s^2 \ 6p^4\) - not a noble gas configuration (f) \(Au^{3+}\): \(1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{10} \ 4f^{14} \ 5s^2 \ 5p^6 \ 5d^{9} \ 6s^1\) - not a noble gas configuration Out of these ions, only \(As^{3-}\) and \(Y^{3+}\) have noble-gas configurations (matching Kr).

Step by step solution

01

Identify the atomic number of each ion

Look at the periodic table and find the atomic number (number of protons) of the neutral atom. This will also give us the number of electrons in the neutral atom since the number of protons equals the number of electrons in a neutral atom.
02

Determine the number of electrons in the ion

Calculate the number of electrons in the ion by adding or subtracting the given charge from the atomic number of the neutral atom.
03

Write the electron configuration for each ion

Based on the number of electrons, write down the electron configuration for each ion, following the filling order of subshells.
04

Check if the electron configurations match any noble gases

Look at the periodic table and see if any of the ions' electron configurations match those of noble gases. Now, let's go through each ion and write their electron configurations.
05

Electron configuration of Ru^{3+}

Ru (Ruthenium) has an atomic number of 44. Ru^{3+} ion means three electrons are removed from the neutral atom, so we have 44 - 3 = 41 electrons. The electron configuration will be: \[1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{7}\] This does not match any noble gas configuration.
06

Electron configuration of As^{3-}

As (Arsenic) has an atomic number of 33. As^{3-} ion means three electrons are added to the neutral atom, so we have 33 + 3 = 36 electrons. The electron configuration will be: \[1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6\] This matches the electron configuration of a noble gas: Kr (Krypton).
07

Electron configuration of Y^{3+}

Y (Yttrium) has an atomic number of 39. Y^{3+} ion means three electrons are removed from the neutral atom, so we have 39 - 3 = 36 electrons. The electron configuration will be: \[1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6\] This matches the electron configuration of a noble gas: Kr (Krypton).
08

Electron configuration of Pd^{2+}

Pd (Palladium) has an atomic number of 46. Pd^{2+} ion means two electrons are removed from the neutral atom, so we have 46 - 2 = 44 electrons. The electron configuration will be: \[1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{8}\] This does not match any noble gas configuration.
09

Electron configuration of Pb^{2+}

Pb (Lead) has an atomic number of 82. Pb^{2+} ion means two electrons are removed from the neutral atom, so we have 82 - 2 = 80 electrons. The electron configuration will be: \[1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{10} \ 4f^{14} \ 5s^2 \ 5p^6 \ 5d^{10} \ 6s^2 \ 6p^4\] This does not match any noble gas configuration.
10

Electron configuration of Au^{3+}

Au (Gold) has an atomic number of 79. Au^{3+} ion means three electrons are removed from the neutral atom, so we have 79 - 3 = 76 electrons. The electron configuration will be: \[1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^6 \ 3d^{10} \ 4s^2 \ 4p^6 \ 4d^{10} \ 4f^{14} \ 5s^2 \ 5p^6 \ 5d^{9} \ 6s^1\] This does not match any noble gas configuration. From the electron configurations, we can see that only the As^{3-} and Y^{3+} ions have noble-gas configurations (matching Kr).

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Most popular questions from this chapter

Using only the periodic table, arrange each set of atoms in order of increasing radius: (a) Ba, Ca, Na; (b) In, Sn, As; (c) Al, Be, Si.

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