Would a neutral \(\mathrm{K}\) atom or a \(\mathrm{K}^{+}\) ion have a more negative value of electron affinity?

Short Answer

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A neutral Potassium atom (K) would have a more negative value of electron affinity compared to a K+ ion. This is because a neutral K atom releases energy when gaining an electron, while a K+ ion, having the same electron configuration as the noble gas argon (Ar), would require extra energy to attract an electron due to its already full electron configuration.

Step by step solution

01

Understand electron affinity

Electron affinity is defined as the amount of energy released when an electron is added to a neutral atom, forming a negatively charged ion. It's an indication of how much an atom wants to gain an electron. In general, elements with higher electron affinity have a stronger attraction for electrons. A more negative value of electron affinity means that a greater amount of energy is released when an electron is added, which implies that the atom (or ion) has a stronger tendency to attract electrons.
02

Analyze the electron configurations of K and K+.

To analyze the electron configurations of a neutral K atom and a K+ ion, we need to know the atomic number of potassium, which is 19. Neutral K atom: - Atomic number: 19 - Electron configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ K+ ion (after losing one electron): - Cation with a charge of +1 (one electron less) - Electron configuration: 1s² 2s² 2p⁶ 3s² 3p⁶
03

Compare the electron affinity of K and K+.

Now let's compare their electron affinity values: 1. For the neutral potassium atom (K), when an electron is added to the 4s orbital, it will result in the formation of a negatively charged ion: K⁻. Since there is a considerable amount of energy released in this process, potassium has a negative value of electron affinity. 2. For the K+ ion, it already lost one electron and its electron configuration now is the same as that of argon (Ar), which is a noble gas. As noble gases have already achieved full electron configurations (completely filled orbitals), they inherently have a very low tendency to attract or gain any more electrons. Therefore, if an electron is forcibly added, it would not release any energy, rather, it would require extra energy for this process. So, in the case of the K+ ion, the electron affinity will be either zero or a positive value.
04

Determine which one has a more negative electron affinity.

Since a neutral K atom has a negative electron affinity, whereas a K+ ion has an electron affinity of either zero or a positive value, we can conclude that a neutral Potassium atom (K) would have a more negative value of electron affinity compared to a K+ ion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Chemical Properties
Chemical properties are attributes that we cannot observe without causing a substance to change into something else. These properties are a direct result of the arrangements of atoms and their components, especially electrons, within atoms and molecules.

For example, when discussing the chemical properties of potassium (K), we examine its reactivity with water, its valence electron configuration, and its affinity to gain electrons, which includes electron affinity. In our exercise with potassium, we notice that a neutral K atom has a distinct chemical property compared to the K+ ion when it comes to gaining electrons. The neutral atom is much more inclined to accept an additional electron, which is evident from its more negative value of electron affinity.

Understanding chemical properties requires not only an analysis of the atom's current state but also a prediction of its behavior as it gains or loses electrons. This extends to how an atom interacts in reactions, whether through ionic bonding, covalent bonding, or other chemical reactions.
Ionization Energy Explained
Ionization energy is the energy required to remove an electron from an atom or ion in its gaseous state. It's an essential concept when understanding why atoms form ions, which is a pivotal part of predicting and explaining the chemical behavior of elements.

For instance, in the case of our textbook problem, the ionization energy of potassium (K) is considered when it loses an electron to form a K+ ion. After losing that electron, the ionization energy would be significantly higher for removing another electron, as the electron configuration has become stable resembling that of a noble gas.

This can be connected to electron affinity as well; the K+ ion does not readily accept an additional electron, partly because after losing its outermost electron, the energy required to remove another electron from the now stable configuration increases dramatically. In essence, a higher ionization energy often corresponds with a lower willingness to attract additional electrons, which is seen in our problem with the K+ ion.
Electron Configurations and Their Impact
Electron configurations refer to the distribution of electrons in an atom's orbitals and provide a foundation for understanding an element’s reactivity and the types of bonds it can form.

Analyzing potassium’s electron configuration, a neutral K atom ends with the electron configuration 4s¹, indicating a single electron in its outermost shell. This electron is relatively loosely bound compared to those in full orbitals, influencing properties such as ionization energy and electron affinity. When potassium forms a K+ ion, it loses this electron, resulting in a noble gas configuration, which is highly stable and nonreactive.

Furthermore, this change in electron configuration from the neutral K atom to the K+ ion illustrates why the ion has a different how electron affinity. While a neutral atom may be inclined to gain an electron to achieve a more stable state, once it has achieved a stable configuration as seen in the K+ ion, the desire to gain additional electrons significantly decreases.

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Most popular questions from this chapter

Little is known about the properties of astatine, At, because of its rarity and high radioactivity. Nevertheless, it is possible for us to make many predictions about its properties. (a) Do you expect the element to be a gas, liquid, or solid at room temperature? Explain. (b) Would you expect At to be a metal, nonmetal, or metalloid? Explain. (c) What is the chemical formula of the compound it forms with Na?

(a) Why is calcium generally more reactive than magnesium? (b) Why is calcium generally less reactive than potassium?

Potassium superoxide, \(\mathrm{KO}_{2},\) is often used in oxygen masks (such as those used by firefighters) because \(\mathrm{KO}_{2}\) reacts with \(\mathrm{CO}_{2}\) to release molecular oxygen. Experiments indicate that 2 \(\mathrm{mol}\) of \(\mathrm{KO}_{2}(s)\) react with each mole of= \(\mathrm{CO}_{2}(g) .\) (a) The products of the reaction are \(\mathrm{K}_{2} \mathrm{CO}_{3}(s)\) and \(\mathrm{O}_{2}(g) .\) Write a balanced equation for the reaction between \(\mathrm{KO}_{2}(s)\) and \(\mathrm{CO}_{2}(g) .(\mathbf{b})\) Indicate the oxidation number for each atom involved in the reaction in part (a). What elements are being oxidized and reduced? (c) What mass of \(\mathrm{KO}_{2}(s)\) is needed to consume 18.0 \(\mathrm{g} \mathrm{CO}_{2}(g) ?\) What mass of \(\mathrm{O}_{2}(g)\) is produced during this reaction?

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity. (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}^{-} .\) Write out the process corresponding to the first ionization energy of the hydride ion. (e) How does the process in part (d) compare to the process for the electron affinity of a neutral hydrogen atom?

Write equations that show the process for (a) the first two ionization energies of lead and (b) the fourth ionization energy of zirconium.

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