What is the relationship between the ionization energy of an anion with a \(1-\) charge such as \(F^{-}\) and the electron affinity of the neutral atom, \(\mathrm{F}\) ?

Short Answer

Expert verified
The relationship between the ionization energy of an anion with a $1-$ charge such as \(F^{-}\) and the electron affinity of the neutral atom, F, can be expressed as: \( Ionization\:Energy\:of\:F^{-} = - Electron\:Affinity\:of\:F \). This indicates that the magnitudes of the ionization energy and electron affinity are equal, but the signs are opposite, as ionization energy corresponds to an endothermic process, while electron affinity corresponds to an exothermic process.

Step by step solution

01

Define Ionization Energy and Electron Affinity

Ionization energy is the energy required to remove an electron from an atom or an ion. Electron affinity is the energy change associated with the addition of an electron to a neutral atom, forming a negatively charged ion (anion).
02

Understand Ionization Energy of F⁻ and Electron Affinity of F

Since F⁻ is a negatively charged ion (anion), its ionization energy refers to the energy required to remove an electron from F⁻ to form a neutral F atom. For the neutral F atom, electron affinity refers to the energy change when an electron is added to F, forming the anion F⁻.
03

Relate Ionization Energy of F⁻ and Electron Affinity of F

Here, we can see that both the ionization energy and the electron affinity refer to the same process but in opposite directions (ionization energy is the energy required when going from F⁻ to F, and electron affinity is the energy change when going from F to F⁻). Thus, their magnitudes are equal but the energy signs are opposite because the ionization energy corresponds to removing an electron (endothermic process), while electron affinity corresponds to the addition of an electron (exothermic process).
04

Write the Relationship Between Ionization Energy of F⁻ and Electron Affinity of F

The relationship can be written as: \( Ionization\:Energy\:of\:F^{-} = - Electron\:Affinity\:of\:F \) This relationship indicates that the magnitude of the ionization energy for an anion such as F⁻ is equal to the magnitude of the electron affinity for the corresponding neutral F atom, but the signs are opposite.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionization Energy
Imagine you have a collection of tiny particles, each one unique in its own way. These particles are the atoms and ions that make up the world around us. Among the various properties that we use to understand their behavior is something called ionization energy. Think of ionization energy as the strength needed to persuade an electron to leave the comfort of its atom.

For atoms like the fluoride ion, F⁻, which is our character with a negative charge, this energy is like convincing someone who loves their home that it's time to move out. It's a measure of how much energy is required to remove an electron from an ion or an atom. When it comes to an anion (a negatively charged ion), which already has an extra electron it is fond of, the ionization energy is quite high because the extra electron is experiencing a strong attraction to the positively charged protons in the nucleus.

Hence, the ionization energy for negatively charged ions is significant. It is an important concept in understanding the energetic aspects of elements and how they interact or form bonds in the beautiful dance of chemistry.
Electron Affinity
On the flip side of our atomic coin is electron affinity, which could be likened to a measure of how much an atom wants to adopt an electron. Taking the case of a neutral fluorine atom, its electron affinity is a bit like the excitement and readiness of a home awaiting a new family member. The electron affinity of an atom is the energy change that occurs when an electron is added to a lone atom, bonding them together to form a negatively charged ion or anion.

For fluorine, the addition of an electron is a very exothermic process, meaning it releases energy, and this reflects the high electron affinity of the atom. The neutral fluorine atom is like a watchdog eager for the company, practically springing towards the approaching electron to create a more stable F⁻ ion. This eagerness translates into a stronger bond, and such energy nuances have profound implications on how substances form and how they engage in chemical reactions.
Anion
Our third and final concept spirals into the world of anions. These are not just any ordinary members of the atomic table; they're actually atoms that have gained an extra electron, giving them an overall negative charge. They're the socialites of the periodic table, always eager to add more electrons to their entourage.

Let’s stay in the same corner and talk about our fluoride ion, F⁻. Here we have a classic example of an anion, a fluorine atom that has joyfully embraced an extra electron into its fold. This adoption of a new electron is often a favorable move for the atom, as it achieves a more stable, noble gas electron configuration. Anions are significant players in the realm of chemistry, as they're the negatively charged party goers that react with positively charged ions (cations) to produce various compounds, ranging from the salt in your kitchen to the minerals in the Earth's crust.

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Most popular questions from this chapter

(a) Which ion is smaller, \(\mathrm{Co}^{3+}\) or \(\mathrm{Co}^{4+} ?(\mathbf{b})\) In a lithium-ion battery that is discharging to power a device, for every \(\mathrm{Li}^{+}\) that inserts into the lithium cobalt oxide electrode, a \(\mathrm{Co}^{4+}\) ion must be reduced to a \(\mathrm{Co}^{3+}\) ion to balance charge. Using the CRC Handbook of Chemistry and Physics or other standard reference, find the ionic radii of \(\mathrm{Li}^{+}, \mathrm{Co}^{3+},\) and \(\mathrm{Co}^{4+} .\) Order these ions from smallest to largest. (c) Will the lithium cobalt oxide cathode expand or contract as lithium ions are inserted? (d) Lithium is not nearly as abundant as sodium. If sodium ion batteries were developed that function in the same manner as lithium ion batteries, do you think "sodium cobalt oxide" would still work as the electrode material? Explain. (e) If you don’t think cobalt would work as the redox-active partner ion in the sodium version of the electrode, suggest an alternative metal ion and explain your reasoning.

The electron affinities, in \(\mathrm{kJ} / \mathrm{mol},\) for the group 1 \(\mathrm{B}\) and group 2 \(\mathrm{B}\) metals are as follows: (a) Why are the electron affinities of the group 2 \(\mathrm{B}\) elements greater than zero? (b) Why do the electron affinities of the group 1 \(\mathrm{B}\) elements become more negative as we move down the group? [Hint: Examine the trends in the electron affinities of other groups as we proceed down the periodic table.]

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity. (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}^{-} .\) Write out the process corresponding to the first ionization energy of the hydride ion. (e) How does the process in part (d) compare to the process for the electron affinity of a neutral hydrogen atom?

Tungsten has the highest melting point of any metal in the periodic table: \(3422^{\circ} \mathrm{C}\) . The distance between \(\mathrm{W}\) atoms in tungsten metal is 2.74 A. (a) What is the atomic radius of atungsten atom in this environment? (This radius is called the metallic radius.) If you put tungsten metal under high pressure, predict what would happen to the distance between \(\mathrm{W}\) atoms.

Detailed calculations show that the value of \(Z_{\text { eff }}\) for the outermost electrons in Si and Cl atoms is \(4.29+\) and \(6.12+\) , respectively.(a) What value do you estimate for \(Z\) eff experienced by the outermost electron in both Si and Cl by assuming core electrons contribute 1.00 and valence electrons contribute 0.00 to the screening constant? (b) What values do you estimate for \(Z_{\text { eff }}\) using Slater's rules? (c) Which approach gives a more accurate estimate of \(Z_{\text { eff? }} ?(\mathbf{d})\) Which method of approximation more accurately accounts for the steady increase in \(Z_{\text { eff }}\) that occurs upon moving left to right across a period? (e) Predict \(Z_{\text { eff }}\) for a valence electron in \(\mathrm{P}\) , phosphorus, based on the calculations for Si and Cl.

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