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Chapter 7: Problem 77

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Ozone decomposes to dioxygen. (b) Xenon reacts with fluorine. (Write three different equations.) (c) Sulfur reacts with hydrogen gas. (d) Fluorine reacts with water.

Short Answer

Expert verified
(a) \(2O_3 → 3O_2\) (b) 1. \(Xe + 3F_2 → XeF_6\) 2. \(Xe + 2F_2 → XeF_4\) 3. Xe + F2 → XeF2 (c) \(S + 2H_2 → 2H_2S\) (d) \(F_2 + H_2O → OF_2 + 2HF\)

Step by step solution

01

Identify reactants and products

The given information is that ozone (O3) decomposes into dioxygen (O2). So, ozone is the reactant and dioxygen is the product.
02

Write the unbalanced equation

The unbalanced equation for the decomposition of ozone is: O3 → O2
03

Balance the equation

In the unbalanced equation, there are three oxygen atoms on the left and two oxygen atoms on the right. To balance the equation, we should multiply the product side by \(\frac{3}{2}\). However, we cannot have a fraction as a coefficient in a balanced equation, so we will multiply both sides by 2 to establish whole number coefficients. Therefore, the balanced equation is: \[2O_3 → 3O_2\] ### Case (b): Xenon reacts with fluorine (3 different equations) ###
04

Identify reactants, possible products, and write the unbalanced equations

The given information is that xenon (Xe) reacts with fluorine (F2). So, xenon and fluorine are the reactants. Xenon can form multiple fluorides: XeF2, XeF4, and XeF6. We will write the balanced equation for each case.
05

Balance the equations

1. For Xenon Hexafluoride (XeF6): Unbalanced equation: Xe + F2 → XeF6 To balance this equation, add a coefficient of 3 to F2: \[Xe + 3F_2 → XeF_6\] 2. For Xenon Tetrafluoride (XeF4) Unbalanced equation: Xe + F2 → XeF4 To balance this equation, add a coefficient of 2 to F2: \[Xe + 2F_2 → XeF_4\] 3. For Xenon Difluoride (XeF2) Unbalanced equation: Xe + F2 → XeF2 This equation is already balanced. ### Case (c): Sulfur reacts with hydrogen gas ###
06

Identify reactants and products

The given information is that sulfur (S) reacts with hydrogen gas (H2). So, sulfur and hydrogen gas are the reactants, and the product is Hydrogen Sulfide (H2S).
07

Write the unbalanced equation

The unbalanced equation for the reaction between sulfur and hydrogen gas is: S + H2 → H2S
08

Balance the equation

To balance the equation, add a coefficient of 2 to H2S: \[S + 2H_2 → 2H_2S\] ### Case (d): Fluorine reacts with water ###
09

Identify reactants and products

The given information is that fluorine (F2) reacts with water (H2O). So, fluorine and water are the reactants, and the products are Oxygen Difluoride (OF2) and Hydrogen Fluoride (HF).
10

Write the unbalanced equation

The unbalanced equation for the reaction between fluorine and water is: F2 + H2O → OF2 + HF
11

Balance the equation

To balance this equation, add a coefficient of 2 to HF: \[F_2 + H_2O → OF_2 + 2HF\]

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Most popular questions from this chapter

If the electron affinity for an element is a negative number, does it mean that the anion of the element is more stable than the neutral atom? Explain.

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