What is the Lewis symbol for each of the following atoms or ions? (a) \(\mathrm{K},\) (b) As, (c) \(\mathrm{Sn}^{2+},(\mathbf{d}) \mathrm{N}^{3-}\) .

Short Answer

Expert verified
The Lewis symbols for the given atoms and ions are: (a) \(\text{K}\bullet\) , (b) \[\begin{array}{c}\cdot \text{As} \cdot \\ | \end{array}\], (c) \(\bullet \text{Sn}^{2+} \bullet\), and (d) \[\begin{array}{c}\cdot \text{N}^{3-} \cdot \\ | \end{array}\].

Step by step solution

01

Determine valence electrons for each atom/ion

(a) Potassium (K) - As it belongs to the first group in the periodic table, it has only 1 valence electron. (b) Arsenic (As) - Being a member of Group 15 in the periodic table, it has 5 valence electrons. (c) Tin(II) ion (Sn²⁺) - Tin, as a Group 14 element, has 4 valence electrons. However, due to the 2+ charge, which means it loses 2 electrons, that leaves it with 2 valence electrons. (d) Nitride ion (N³⁻) - Nitrogen, as a Group 15 element, has 5 valence electrons. Since the ion has a 3- charge, it gains 3 electrons, thus giving it a total of 8 valence electrons.
02

Represent elements and ions with their symbols and valence electrons

(a) Potassium (K) - \[\text{K}\bullet\] (b) Arsenic (As) - \[\begin{array}{c}\cdot \text{As} \cdot \\ | \end{array}\] (c) Tin(II) ion (Sn²⁺) - \[\bullet \text{Sn}^{2+} \bullet\] (d) Nitride ion (N³⁻) - \[\begin{array}{c}\cdot \text{N}^{3-} \cdot \\ | \end{array}\] The Lewis symbols for the given atoms and ions are: (a) K• , (b) ∙As∙| , (c) •Sn²⁺• , and (d) ∙N³⁻∙| .

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