Consider the ionic compounds KF, NaCl, NaBr, and LiCl. (a) Use ionic radil (Figure 7.8) to estimate the cation-anion distance for each compound. (b) Based on your answer to part (a), arrange these four compounds in order of decreasing lattice energy. (c) Check your predictions in part (b) with the experimental values of lattice energy from Table \(8.1 .\) Are the predictions from ionic radii correct?

Short Answer

Expert verified
The cation-anion distances for KF, NaCl, NaBr, and LiCl are 252 pm, 264 pm, 279 pm, and 227 pm respectively. Based on these distances, the order of decreasing lattice energy is LiCl, KF, NaCl, and NaBr. This order is confirmed by the experimental lattice energy values from Table 8.1: LiCl (853 kJ/mol), KF (821 kJ/mol), NaCl (787 kJ/mol), and NaBr (747 kJ/mol). Thus, the predictions based on ionic radii are correct.

Step by step solution

01

Calculate the cation-anion distances for each compound

For each compound, add the ionic radii of the cation and anion to find the cation-anion distance. Use Figure 7.8 to find the ionic radii. For KF: - K⁺ radius: 133 pm - F⁻ radius: 119 pm Cation-anion distance = 133 pm + 119 pm = 252 pm For NaCl: - Na⁺ radius: 97 pm - Cl⁻ radius: 167 pm Cation-anion distance = 97 pm + 167 pm = 264 pm For NaBr: - Na⁺ radius: 97 pm - Br⁻ radius: 182 pm Cation-anion distance = 97 pm + 182 pm = 279 pm For LiCl: - Li⁺ radius: 60 pm - Cl⁻ radius: 167 pm Cation-anion distance = 60 pm + 167 pm = 227 pm
02

Arrange compounds in order of decreasing lattice energy

Lattice energy is inversely proportional to the distance between the cation and anion. Smaller cation-anion distance results in stronger attractive forces and thus higher lattice energy. Using the cation-anion distance found above, we can arrange the compounds in order of decreasing lattice energy: 1. LiCl (227 pm) 2. KF (252 pm) 3. NaCl (264 pm) 4. NaBr (279 pm)
03

Compare the predicted order with experimental values

Now, let's compare our prediction with the experimental values of lattice energy from Table 8.1. The lattice energies (in kJ/mol) for the compounds are: - KF: 821 kJ/mol - NaCl: 787 kJ/mol - NaBr: 747 kJ/mol - LiCl: 853 kJ/mol Based on the experimental values, the order of decreasing lattice energy is: 1. LiCl (853 kJ/mol) 2. KF (821 kJ/mol) 3. NaCl (787 kJ/mol) 4. NaBr (747 kJ/mol) This confirms that our predictions based on ionic radii are indeed correct.

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Most popular questions from this chapter

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