Using only the periodic table as your guide, select the most electronegative atom in each of the following sets: (a) Na, \(\mathrm{Mg}, \mathrm{K}, \mathrm{Ca} ;(\mathbf{b}) \mathrm{P}, \mathrm{S},\) As, \(\mathrm{Se} ;(\mathbf{c}) \mathrm{Be}, \mathrm{B}, \mathrm{C}, \mathrm{Si} ;(\mathbf{d}) \mathrm{Zn}, \mathrm{Ge}, \mathrm{Ga}, \mathrm{Gs}\)

Short Answer

Expert verified
The most electronegative elements in each set are: (a) $\mathrm{Mg}$; (b) $\mathrm{S}$; (c) $\mathrm{C}$; (d) $\mathrm{Ga}$.

Step by step solution

01

Set (a): Na, Mg, K, Ca

To determine the most electronegative atom among Na, Mg, K, and Ca, we need to locate these elements in the periodic table. They are all in the same period (Period 3) and belong to Groups 1 and 2. As electronegativity increases from left to right across a period, Mg (Group 2) is more electronegative than Na (Group 1). Similarly, Ca (Group 2) is more electronegative than K (Group 1). Between Mg and Ca, since electronegativity decreases down a group, Mg is more electronegative than Ca. Therefore, Mg is the most electronegative element in the given set.
02

Set (b): P, S, As, Se

To determine the most electronegative atom among P, S, As, and Se, we need to locate these elements in the periodic table. They belong to Groups 15 and 16. From left to right in the periodic table, electronegativity increases, so S (Group 16) is more electronegative than P (Group 15) and Se (Group 16) is more electronegative than As (Group 15). Between S and Se, since electronegativity decreases down a group, S is more electronegative than Se. Therefore, S is the most electronegative element in the given set.
03

Set (c): Be, B, C, Si

To determine the most electronegative atom among Be, B, C, and Si, we need to locate these elements in the periodic table. They are all in the same period (Period 2) and belong to Groups 13 and 14. As electronegativity increases from left to right across a period, C (Group 14) is more electronegative than B (Group 13) and Si (Group 14). Between C and Si, since electronegativity decreases down a group, C is more electronegative than Si. Therefore, C is the most electronegative element in the given set.
04

Set (d): Zn, Ge, Ga, Gs

To determine the most electronegative atom among Zn, Ge, Ga, and Gs, we need to locate these elements in the periodic table. They belong to Groups 12, 13, and 14. From left to right in the periodic table, electronegativity increases, so Gs (Group 14) is more electronegative than Ge (Group 13) and Ga (Group 13) is more electronegative than Zn (Group 12). Between Gs and Ga, since electronegativity increases from bottom to top in a group, Ga is more electronegative than Gs. Therefore, Ga is the most electronegative element in the given set.

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