In which of the following \(\mathrm{AF}_{n}\) molecules or ions is there more than one \(\mathrm{F}-\mathrm{A}-\mathrm{Fbond}\) angle: \(\mathrm{SiF}_{4}, \mathrm{PF}_{5}, \mathrm{SF}_{4}, \mathrm{AsF}_{3} ?\)

Short Answer

Expert verified
The molecules with more than one F-A-F bond angle are \(PF_5\) and \(SF_4\).

Step by step solution

01

Determine the Electron Domain Geometry (EDG) and Molecular Geometry (MG) for each molecule/ion

To determine EDG and MG, we can use the VSEPR (Valence Shell Electron Pair Repulsion) theory. The steps for this are: 1. Determine the central atom 2. Calculate the number of surrounding atoms and electron pairs around the central atom 3. Determine the shape/geometry based on VSEPR
02

SiF4

In SiF4, Si is the central atom. It has 4 surrounding F atoms and no lone pairs. This gives us a total of 4 electron domains (4 bonding pairs). Thus, the EDG is tetrahedral, and given that all surrounding atoms are the same, the MG is the same. It is a tetrahedral molecule with a single F-Si-F bond angle of 109.5°.
03

PF5

In PF5, P is the central atom, and it's surrounded by 5 F atoms with no lone pairs. This results in a total of 5 electron domains (5 bonding pairs). The EDG is trigonal bipyramidal, and the MG is the same. There are two types of bond angles for a trigonal bipyramidal molecule: axial F-P-F bond angles (two of them, 180° each) and equatorial F-P-F bond angles (three of them, 120° each).
04

SF4

In SF4, S is the central atom, with 4 F atoms bonded to it and one lone pair. This gives a total of 5 electron domains (4 bonding pairs and 1 lone pair). The EDG is trigonal bipyramidal, and the MG is "see-saw". Here, we have two S-F bond angles of approximately 120° and two F-S-F bond angles of approximately 180°.
05

AsF3

In AsF3, As is the central atom, and it's surrounded by 3 F atoms and one lone pair. This results in a total of 4 electron domains (3 bonding pairs and 1 lone pair). The EDG is tetrahedral, and the MG is trigonal pyramidal. The molecule has only one F-As-F bond angle of 107.7°.
06

Identify the molecules/ions with more than one F-A-F bond angle

Now that we've determined the molecular geometries, we can identify which molecules/ions have more than one F-A-F bond angle: - SiF4: Only one bond angle, not suitable. - PF5: More than one bond angle (axial and equatorial), suitable. - SF4: More than one bond angle (approximately 120° and 180° angles), suitable. - AsF3: Only one bond angle, not suitable. Therefore, the molecules with more than one F-A-F bond angle are \(PF_5\) and \(SF_4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
Understanding molecular geometry is crucial for determining how molecules will interact with one another, their reactivity, boiling and melting points, and even how they might smell or taste. In essence, molecular geometry is the three-dimensional arrangement of atoms within a molecule. It is determined by the number of electron pairs, both bonding and non-bonding (lone pairs), surrounding the central atom.

In our exercise, for example, the molecular geometry of SiF4 is tetrahedral because the silicon atom is surrounded by four fluorine atoms with no lone pairs. This symmetrical shape means all F-Si-F bond angles are equal to 109.5°. On the other hand, SF4 has a 'see-saw' shape due to the presence of a lone pair which distorts the ideal tetrahedral angle, leading to F-S-F bond angles that are not equivalent. This is why understanding molecular geometry is essential in predicting the behavior of molecules.
Electron Domain Geometry
The concept of electron domain geometry (EDG) is intimately linked to the VSEPR theory. It refers to the spatial arrangement of both the bonding and the lone pair electron domains around the central atom. By 'electron domain,' we mean a region where electrons are most likely to be found. Each bond, no matter if it's single, double, or triple, counts as one electron domain, and each lone pair is also one domain.

Electron domains repel each other and try to get as far apart as possible. In PF5, the phosphorus is surrounded by five bonding pairs of electrons, which arrange themselves in a trigonal bipyramidal fashion as per EDG. This means there are two different types of bond angles, axial and equatorial, due to the three-dimensional spacing of the electron domains around the central atom.
Bond Angles
The measurement of the angle between two adjacent bonds in a molecule is known as a bond angle. These angles give us specific insights into the molecular geometry of a substance. The VSEPR theory helps predict the bond angles based on the repulsion between electron domains—representing both lone pairs and bonded atoms.

For instance, the ideal tetrahedral bond angle is 109.5°, as seen in SiF4. However, the presence of lone pairs like in AsF3 reduces the bond angle to 107.7° because lone pairs exert more repulsion than bonding pairs. In a molecule like PF5, the axial and equatorial F-P-F bond angles are 180° and 120°, respectively, because of the trigonal bipyramidal EDG. Hence, comprehending bond angles provides a foundation for understanding broader molecular behavior and structure.

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Most popular questions from this chapter

(a) Methane \(\left(\mathrm{CH}_{4}\right)\) and the perchlorate ion \(\left(\mathrm{ClO}_{4}^{-}\right)\) are both described as tetrahedral. What does this indicate about their bond angles? (b) The \(\mathrm{NH}_{3}\) molecule is trigonal pyramidal, while \(\mathrm{BF}_{3}\) is trigonal planar. Which of these molecules is flat?

Predict whether each of the following molecules is polar or nonpolar: (a) IF, (b) \(\mathrm{CS}_{2},(\mathbf{c}) \mathrm{SO}_{3},(\mathbf{d}) \mathrm{PCl}_{3},(\mathbf{e}) \mathrm{SF}_{6},(\mathbf{f}) \mathrm{IF}_{5}\)

The phosphorus trihalides \(\left(\mathrm{PX}_{3}\right)\) show the following variation in the bond angle \(\mathrm{X}-\mathrm{P}-\mathrm{X} : \mathrm{PF}_{3}, 96.3^{\circ} ; \mathrm{PCl}_{3}, 100.3^{\circ}\) ; \(\mathrm{PBr}_{3}, 101.0^{\circ} ; \mathrm{PI}_{3}, 102.0^{\circ} .\) The trend is generally attributed to the change in the electronegativity of the halogen. (a) Assuming that all electron domains are the same size, what value of the \(X-P-X\) angle is predicted by the VSEPR model? (b) What is the general trend in the \(X-P-X\) angle as the halide electronegativity increases? (c) Using the VSEPR model, explain the observed trend in \(X-P-X\) angle as the electronegativity of \(X\) changes. (d) Based on your answer to part (c), predict the structure of \(\mathrm{PBrCl}_{4}\)

Indicate the hybridization of the central atom in \((\mathbf{a}) \mathrm{BCl}_{3}$$(\mathbf{b}) \mathrm{AlCl}_{4}^{-},(\mathbf{c}) \mathrm{CS}_{2},(\mathbf{d}) \mathrm{GeH}_{4}\)

The Lewis structure for allene is Make a sketch of the structure of this molecule that is analogous to Figure \(9.25 .\) In addition, answer the following three questions: (a) Is the molecule planar? (b) Does it have a nonzero dipole moment? (c) Would the bonding in allene be described as delocalized? Explain.

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