Indicate the number of significant figures in each of the following measured quantities: (a) \(62.65 \mathrm{~km} / \mathrm{hr}\), (b) \(78.00 \mathrm{~K}\), (c) \(36.9 \mathrm{~mL}\) (d) \(250 \mathrm{~mm}\), (e) 89.2 metric tons, (f) \(6.4224 \times 10^{2} \mathrm{~m}^{3}\)

Short Answer

Expert verified
(a) 4 significant figures, (b) 4 significant figures, (c) 3 significant figures, (d) 2 significant figures, (e) 3 significant figures, (f) 5 significant figures.

Step by step solution

01

:For the given quantity, all the digits (6, 2, 6, and 5) are non-zero and there are no zeros between non-zero digits. Hence, all the digits are considered significant. Therefore, there are 4 significant figures in \(62.65 \mathrm{~km}/\mathrm{hr}\). ##Step 2: Determine the significant figures in (b) \(78.00 \mathrm{~K}\).##

:In this case, we have two non-zero digits (7 and 8) and two trailing zeros after the decimal point (0 and 0). Since the number has a decimal point, the trailing zeros are significant. Thus, there are 4 significant figures in \(78.00 \mathrm{~K}\). ##Step 3: Determine the significant figures in (c) \(36.9 \mathrm{~mL}\).##
02

:Here, all the digits (3, 6, and 9) are non-zero, and there are no zeros between non-zero digits. Therefore, there are 3 significant figures in \(36.9 \mathrm{~mL}\). ##Step 4: Determine the significant figures in (d) \(250 \mathrm{~mm}\).##

:For this quantity, we have two non-zero digits (2 and 5) and one trailing zero without a decimal point (0). The trailing zero is not considered significant since there is no decimal point. Thus, there are 2 significant figures in \(250 \mathrm{~mm}\). ##Step 5: Determine the significant figures in (e) 89.2 metric tons.##
03

:In this case, all the digits (8, 9, and 2) are non-zero. There are no zeros between non-zero digits. Therefore, there are 3 significant figures in 89.2 metric tons. ##Step 6: Determine the significant figures in (f) \(6.4224 \times 10^{2} \mathrm{~m}^{3}\).##

:The number is in scientific notation, which means that only the significant digits are written (6, 4, 2, 2, and 4). There are no zeros between them, so there are 5 significant figures in \(6.4224 \times 10^{2} \mathrm{~m}^{3}\). To summarize the number of significant figures in each measured quantity: (a) 4 significant figures, (b) 4 significant figures, (c) 3 significant figures, (d) 2 significant figures, (e) 3 significant figures, (f) 5 significant figures.

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