The highest barometric pressure ever recorded was 823.7 torr at Agata in Siberia, Russia on December 31,1968 . Convert this pressure to (a) atm, (b) \(\mathrm{mm} \mathrm{Hg}\), (c) pascals, (d) bars, (e) psi.

To convert the given pressure in torr to atm, we can use the following equivalence relation between torr and atm: 1 atm \(\approx\) 760 torr From this equivalence relation, the given pressure in atm is: \( Pressure_{atm} = \frac{Pressure_{torr}}{760torr} \)

Now that we have the pressure in atm, we can convert it to other units using known conversion factors for each of these units. The conversion factors are as follows: a) 1 atm = 760 mmHg b) 1 atm = 101325 Pa c) 1 atm = 1.01325 bar d) 1 atm = 14.696 psi

With the conversion factors established, we can now calculate the pressure in each unit using the pressure in atm: (a) Pressure in atm is already calculated in step 1, so we don't need to convert it. (b) To convert pressure in atm to mmHg: \( Pressure_{mmHg} = Pressure_{atm} \times 760 mmHg \) (c) To convert pressure in atm to Pa: \( Pressure_{Pa} = Pressure_{atm} \times 101325 Pa \) (d) To convert pressure in atm to bar: \( Pressure_{bar} = Pressure_{atm} \times 1.01325 bar \) (e) To convert pressure in atm to psi: \( Pressure_{psi} = Pressure_{atm} \times 14.696 psi \)

Calculate the pressure in each unit by plugging in the value for pressure in atm (from step 1) into the formulas derived in step 3: (a) Pressure in atm: \( Pressure_{atm} = \frac{823.7 torr}{760 torr} = 1.0841 atm \) (b) Pressure in mmHg: \( Pressure_{mmHg} = 1.0841 atm \times 760 mmHg = 823.7 mmHg \) (c) Pressure in Pa: \( Pressure_{Pa} = 1.0841 atm \times 101325 Pa = 109905.4 Pa \) (d) Pressure in bar: \( Pressure_{bar} = 1.0841 atm \times 1.01325 bar = 1.0985 bar \) (e) Pressure in psi: \( Pressure_{psi} = 1.0841 atm \times 14.696 psi = 15.936 psi \) In summary, the highest barometric pressure ever recorded is approximately equivalent to: (a) 1.0841 atm (b) 823.7 mmHg (c) 109905.4 Pa (d) 1.0985 bar (e) 15.936 psi