Radon (Rn) is the heaviest (and only radioactive) member of the noble gases. How much slower is the root-mean-square speed of Rn than He at $300 \mathrm{K?}$

Short Answer

Expert verified
The root-mean-square speed of Radon (Rn) is approximately 1.17 x 10^3 m/s slower than the root-mean-square speed of Helium (He) at 300 K.

Step by step solution

01

Identify the given values and constants

Given values: Temperature (T) = 300 K Constants: Boltzmann constant (k_B) = 1.38 × 10^-23 J/K
02

Find the molar mass of both Helium and Radon

Molar mass of He = 4 g/mol Molar mass of Rn = 222 g/mol
03

Convert molar mass to molecular mass

To convert molar mass to molecular mass, we need to multiply molar mass by the unified atomic mass unit (u). 1 u = 1.66 × 10^-27 kg Molecular mass of He = (4 g/mol) * (1.66 × 10^-27 kg/u) = 6.64 × 10^-27 kg Molecular mass of Rn = (222 g/mol) * (1.66 × 10^-27 kg/u) = 3.68 × 10^-25 kg
04

Calculate the root-mean-square speeds for both Helium and Radon

Now we can plug these values into the root-mean-square formula: \(v_{rms, He} = \sqrt{\frac{3 * 1.38 * 10^{-23} * 300}{6.64 * 10^{-27}}}\) \(v_{rms, He} ≈ 1.38 * 10^3 m/s\) \(v_{rms, Rn} = \sqrt{\frac{3 * 1.38 * 10^{-23} * 300}{3.68 * 10^{-25}}}\) \(v_{rms, Rn} ≈ 2.14 * 10^2 m/s\)
05

Find the difference in root mean square speeds

Now we will find the difference in root mean square speeds of He and Rn: Difference = Speed of He - Speed of Rn Difference = \(1.38 * 10^3 - 2.14 * 10^2 ≈ 1.17 * 10^3 m/s\) The root-mean-square speed of Radon (Rn) is approximately 1.17 x 10^3 m/s slower than the root-mean-square speed of Helium (He) at 300 K.

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