(a) How does the average kinetic energy of molecules compare with the average energy of attraction between molecules in solids, liquids, and gases? (b) Why does increasing the temperature cause a solid substance to change in succession from a solid to a liquid to a gas? (c) What happens to a gas if you put it under extremely high pressure?

Short Answer

Expert verified
In different states of matter, the balance between the average kinetic energy of molecules and the average energy of attraction between them varies. In solids, the energy of attraction is stronger than the kinetic energy, holding molecules in a rigid structure. In liquids, the energy of attraction is weaker, allowing molecules to move more freely but still remain together. In gases, the kinetic energy is higher than the energy of attraction, allowing molecules to move freely and independently. Increasing temperature causes solids to change to liquids and then to gases, as the increased kinetic energy overcomes the energy of attraction between molecules. Extremely high pressure can cause a gas to become a liquid or solid, as the reduction in volume increases the energy of attraction between molecules.

Step by step solution

01

(a) Comparison of kinetic and attraction energies in different states of matter

In different states of matter, the balance between the average kinetic energy of molecules and the average energy of attraction between them varies, leading to different behaviors. Let's discuss each state of matter. 1. Solids: In solids, the average energy of attraction between molecules is relatively high and is stronger than their average kinetic energy. This is due to the molecules being closely packed together, which leads to strong attractive forces. As a result, the molecules are held tightly in place, which defines the rigid structure of solids. 2. Liquids: In liquids, the average energy of attraction is weaker than in solids but still stronger than the average kinetic energy of the molecules. Due to the weaker attraction, the molecules are able to move around each other a bit more freely but are still held together, resulting in the fluid nature of liquids. 3. Gases: In gases, the average kinetic energy of the molecules is higher than the average energy of attraction between them. This is due to the molecules being much farther apart, resulting in weaker attractive forces. Consequently, the molecules move freely and independently of each other which defines the properties of gases.
02

(b) Effect of increasing temperature on solids

Increasing the temperature causes a solid substance to change in succession from a solid to a liquid to a gas due to the relationship between temperature and kinetic energy. At higher temperatures, the average kinetic energy of the molecules increases as they gain energy. This increased energy allows them to overcome the energy of attraction between them, leading to changes in the state of matter. 1. Solid to liquid: As the temperature of a solid increases, the kinetic energy of its molecules increases, allowing them to break free from their rigid structure. This causes the solid to turn into a liquid. 2. Liquid to gas: As the temperature continues to rise, the kinetic energy of the molecules within the liquid increases further, allowing them to overcome the remaining energy of attraction between them. This causes the liquid to turn into a gas.
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(c) Effect of extremely high pressure on gases

When a gas is subjected to extremely high pressure, the volume of the gas decreases causing the molecules within the gas to come closer together. As a result, the energy of attraction between the molecules becomes more significant, leading to a change in the state of matter. Under certain conditions, extremely high pressure can cause the gas to become a solid or a liquid, depending on the specific substance and the temperature it's subjected to.

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Most popular questions from this chapter

Acetone \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\), is a common organic solvent with relatively low melting point \((178 \mathrm{~K})\) and boiling point $(329 \mathrm{~K})\(. The enthalpy of fusion of acetone is \)5.72 \mathrm{~kJ} / \mathrm{mol}\(, and its enthalpy of vaporization is \)29.1 \mathrm{~kJ} / \mathrm{mol}\(. The specific heats of solid and liquid acetone are \)96 \mathrm{~J} / \mathrm{mol}-\mathrm{K}\( and \)125.5 \mathrm{~J} / \mathrm{mol}-\mathrm{K}$ respectively. (a) How much heat is required to convert \(23.0 \mathrm{~g}\) of acetone at \(273 \mathrm{~K}\) to the vapor phase at \(329 \mathrm{~K} ?(\mathbf{b})\) How much heat is required to convert the same amount of acetone at \(77 \mathrm{~K}\) to the vapor phase at $329 \mathrm{~K} ?$

Which of the following affects the vapor pressure of a liquid? (a) Volume of the liquid, \((\mathbf{b})\) surface area, \((\mathbf{c})\) intermolecular attractive forces, (d) temperature, (e) density of the liquid.

Due to the environmental concern of fluorocarbons as refrigerants, a refrigerant based on a mixture of hydrocarbons was used as a replacement. It is a patented blend of ethane, propane, butane, and isobutane. Isobutane has a normal boiling point of \(-12^{\circ} \mathrm{C}\). The molar specific heat of liquid phase and gas phase isobutane are $129.7 \mathrm{~J} / \mathrm{mol}-\mathrm{K}\( and \)95.2 \mathrm{~J} / \mathrm{mol}-\mathrm{K}$ respectively. The heat of vaporization for this compound is $21.3 \mathrm{~kJ} / \mathrm{mol}\(. Calculate the heat required to convert \)25.0 \mathrm{~g}$ of isobutane from a liquid at \(-50^{\circ} \mathrm{C}\) to a gas at $40^{\circ} \mathrm{C}$.

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Suppose the vapor pressure of a substance is measured at two different temperatures. (a) By using the Clausius-Clapeyron equation (Equation 11.1) derive the following relationship between the vapor pressures, \(P_{1}\) and \(P_{2}\), and the absolute temperatures at which they were measured, \(T_{1}\) and \(T_{2}\) : $$ \ln \frac{P_{1}}{P_{2}}=-\frac{\Delta H_{\mathrm{vap}}}{R}\left(\frac{1}{T_{1}}-\frac{1}{T_{2}}\right) $$ (b) Gasoline is a mixture of hydrocarbons, a component of which is octane $\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\right)$. Octane has a vapor pressure of \(1.86 \mathrm{kPa}\) at \(25^{\circ} \mathrm{C}\) and a vapor pressure of \(19.3 \mathrm{kPa}\) at \(75^{\circ} \mathrm{C}\). Use these data and the equation in part (a) to calculate the heat of vaporization of octane. \((\mathbf{c})\) By using the equation in part (a) and the data given in part (b), calculate the normal boiling point of octane. Compare your answer to the one you obtained from Exercise 11.81 . (d) Calculate the vapor pressure of octane at \(-30^{\circ} \mathrm{C}\).

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