At room temperature, \(\mathrm{CO}_{2}\) is a gas, \(\mathrm{CCl}_{4}\) is a liquid, and \(\mathrm{C}_{60}\) (fullerene) is a solid. List these substances in order of (a) increasing intermolecular energy of attraction and (b) increasing boiling point.

Short Answer

Expert verified
In terms of (a) increasing intermolecular energy of attraction and (b) increasing boiling point, the order is CO₂ < CCl₄ < C₆₀. CO₂ has the weakest London dispersion forces, followed by CCl₄, and C₆₀ with the strongest London dispersion forces. Consequently, CO₂ has the lowest boiling point, followed by CCl₄, and C₆₀ with the highest boiling point.

Step by step solution

01

CO₂ < CCl₄ < C₆₀

In terms of increasing intermolecular energy of attraction, it will be CO₂ (with the weakest London dispersion forces), followed by CCl₄, and finally C₆₀ (with the strongest London dispersion forces). #b. Increasing Boiling Point # The boiling point of a substance is directly related to its intermolecular forces. Stronger intermolecular forces lead to higher boiling points because more energy is needed to break the bonds between the molecules.
02

CO₂ < CCl₄ < C₆₀

As CO₂ has the weakest intermolecular forces, it will have the lowest boiling point, followed by CCl₄, and then C₆₀ (with the strongest intermolecular forces) will have the highest boiling point.

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