Look up and compare the normal boiling points and normal melting points of \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{H}_{2} \mathrm{~S}\). Based on these physical properties, which substance has stronger intermolecular forces? What kinds of intermolecular forces exist for each molecule?

Short Answer

Expert verified
The normal boiling points and normal melting points of water (H₂O) and hydrogen sulfide (H₂S) are as follows: - H₂O: Normal boiling point: 100°C, Normal melting point: 0°C - H₂S: Normal boiling point: -60.7°C, Normal melting point: -82°C Comparing these values, we can conclude that H₂O has stronger intermolecular forces due to its higher boiling and melting points. Intermolecular forces for water include strong dipole-dipole interactions and hydrogen bonding, while hydrogen sulfide has weaker dipole-dipole interactions and does not exhibit hydrogen bonding.

Step by step solution

01

Look up the normal boiling points and normal melting points of H₂O and H₂S

We can find the normal boiling points and normal melting points of water (H₂O) and hydrogen sulfide (H₂S) in a chemistry reference book or online. For water (H₂O): - Normal boiling point: 100°C (212°F) - Normal melting point: 0°C (32°F) For hydrogen sulfide (H₂S): - Normal boiling point: -60.7°C (-77.3°F) - Normal melting point: -82°C (-115.6°F)
02

Identify the substance with stronger intermolecular forces

Comparing the normal boiling and melting points, we see that H₂O has much higher boiling and melting points than H₂S. This indicates that H₂O has stronger intermolecular forces, as more energy is required to break these forces and cause a phase transition (from solid to liquid or from liquid to gas).
03

Identify the intermolecular forces in H₂O (water)

There are several types of intermolecular forces, including London dispersion forces, dipole-dipole interactions, and hydrogen bonding. Water contains highly polar O-H bonds due to the difference in electronegativity between oxygen and hydrogen. The oxygen atom carries a partial negative charge, while the hydrogen atoms carry partial positive charges. This results in strong dipole-dipole interactions. In addition, water molecules can form hydrogen bonds (a particularly strong kind of dipole-dipole interaction) due to the presence of highly polar O-H bonds.
04

Identify the intermolecular forces in H₂S (hydrogen sulfide)

Hydrogen sulfide, like water, has polar S-H bonds due to the difference in electronegativity between sulfur and hydrogen. However, the S-H bond is less polar than the O-H bond in water, leading to weaker dipole-dipole interactions. Although hydrogen sulfide also contains polar S-H bonds, it does not exhibit hydrogen bonding because the sulfur atom is not as electronegative as the oxygen atom (hydrogen bonding typically occurs with more electronegative elements like oxygen, nitrogen, and fluorine). In summary, water (H₂O) has stronger intermolecular forces, mainly due to its ability to form hydrogen bonds, while hydrogen sulfide (H₂S) has weaker intermolecular forces due to its less polar bonds and the absence of hydrogen bonding.

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Most popular questions from this chapter

Acetone \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\), is a common organic solvent with relatively low melting point \((178 \mathrm{~K})\) and boiling point $(329 \mathrm{~K})\(. The enthalpy of fusion of acetone is \)5.72 \mathrm{~kJ} / \mathrm{mol}\(, and its enthalpy of vaporization is \)29.1 \mathrm{~kJ} / \mathrm{mol}\(. The specific heats of solid and liquid acetone are \)96 \mathrm{~J} / \mathrm{mol}-\mathrm{K}\( and \)125.5 \mathrm{~J} / \mathrm{mol}-\mathrm{K}$ respectively. (a) How much heat is required to convert \(23.0 \mathrm{~g}\) of acetone at \(273 \mathrm{~K}\) to the vapor phase at \(329 \mathrm{~K} ?(\mathbf{b})\) How much heat is required to convert the same amount of acetone at \(77 \mathrm{~K}\) to the vapor phase at $329 \mathrm{~K} ?$

Name the phase transition in each of the following situations and indicate whether it is exothermic or endothermic: (a) Iodine solid turns to iodine gas when it is heated. (b) Snowflakes turn into water when they fall on an open palm. (c) Droplets of water appear on grass in a cold humid morning. (d) Dry ice gradually disappears when left at room temperature for some period of time.

Which type of intermolecular force accounts for each of these differences? (a) Acetone, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO},\) boils at $56^{\circ} \mathrm{C} ;\( dimethyl sulfoxide or DMSO, (CH \)\left._{3}\right)_{2}$ SO, boils at \(189^{\circ}\) C. (b) \(\mathrm{CCl}_{4}\) is a liquid at atmospheric pressure and room temperature, whereas \(\mathrm{CH}_{4}\) is a gas under the same conditions. \((\mathbf{c})\) \(\mathrm{H}_{2} \mathrm{O}\) boils at \(100^{\circ} \mathrm{C}\) but \(\mathrm{H}_{2} \mathrm{~S}\) boils at \(-60^{\circ} \mathrm{C}\). (d) 1 -propanol boils at \(97^{\circ} \mathrm{C}\), whereas 2 -propanol boils at \(82.6^{\circ} \mathrm{C}\).

Propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) is pressurized into liquid and stored in cylinders to be used as a fuel. The normal boiling point of propane is listed as \(-42^{\circ} \mathrm{C}\). (a) When converting propane into liquid at room temperature of \(25^{\circ} \mathrm{C},\) would you expect the pressure in the tank to be greater or less than atmospheric pressure? How does the pressure within the tank depend on how much liquid propane is in it? (b) Suppose the fuel tank leaks and a few liters of propane escape rapidly. What do you expect would happen to the temperature of the remaining liquid propane in the tank? Explain. (c) How much heat must be added to vaporize $20 \mathrm{~g}\( of propane if its heat of vaporization is \)18.8 \mathrm{~kJ} / \mathrm{mol} ?\( What volume does this amount of propane occupy at \)100 \mathrm{kPa}\( and \)25^{\circ} \mathrm{C} ?$

Freon, \(\mathrm{CCl}_{2} \mathrm{~F}_{2},\) and dichloromethane, \(\mathrm{CH}_{2} \mathrm{Cl}_{2},\) are common organic substances. Freon is a gas with a normal boiling point of \(-29.8^{\circ} \mathrm{C}\); dichloromethane's normal boiling point is \(39.6^{\circ} \mathrm{C}\). Which statement is the best explanation of these data? (a) Dichloromethane can form hydrogen bonds, but freon cannot. (b) Dichloromethane has a larger dipole moment than freon. (c) Freon is more polarizable than dichloromethane.

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