A number of salts containing the tetrahedral polyatomic anion, \(\mathrm{BF}_{4}^{-}\), are ionic liquids, whereas salts containing the somewhat larger tetrahedral ion \(\mathrm{SO}_{4}{ }^{2-}\) do not form ionic liquids. Explain this observation.

Short Answer

Expert verified
Salts containing the tetrahedral polyatomic anion \(\mathrm{BF}_{4}^{-}\) form ionic liquids due to their larger and more diffuse charges, which result in weaker electrostatic forces and reduced lattice energies. This allows for relatively easy separation of ions at lower temperatures. In contrast, salts with the tetrahedral ion \(\mathrm{SO}_{4}{ }^{2-}\) have higher charge density and stronger electrostatic forces, leading to higher lattice energies and melting points, thus preventing the formation of ionic liquids at lower temperatures.

Step by step solution

01

Understanding ionic liquids

Ionic liquids are salts that exist in the liquid state at room temperature or below (typically below 100°C). They have unique properties like high thermal stability, low vapor pressure, and good solvating ability. To become an ionic liquid, a compound must have ionic species with a suitable balance between electrostatic forces and van der Waals forces. Generally, large and asymmetric ions with lower charge density form ionic liquids due to weaker lattice energies and reduced melting points.
02

Comparing the structure of the two ions

Now let's look at the two ions mentioned, \(\mathrm{BF}_{4}^{-}\) and \(\mathrm{SO}_{4}{ }^{2-}\). Both ions have a tetrahedral structure. The \(\mathrm{BF}_{4}^{-}\) anion has one boron atom surrounded by four fluorine atoms, while the \(\mathrm{SO}_{4}{ }^{2-}\) anion has one sulfur atom surrounded by four oxygen atoms.
03

Comparing the charges and polarizability

The \(\mathrm{BF}_{4}^{-}\) anion has a -1 charge whereas the \(\mathrm{SO}_{4}{ }^{2-}\) has a -2 charge. In the case of \(\mathrm{BF}_{4}^{-}\), the charge is distributed over the fluorine atoms due to the electronegativity of the fluorine atom, which results in more diffuse charges and lower overall charge density. In contrast, the oxygen atoms in the \(\mathrm{SO}_{4}{ }^{2-}\) anion have more localized charges due to their lesser electronegativity compared to fluorine, which leads to a higher overall charge density.
04

Relating the properties of the ions to ionic liquids formation

The larger, more diffuse charges present in \(\mathrm{BF}_{4}^{-}\) results in weaker electrostatic forces and reduced lattice energies. The lower lattice energies enable relatively easy separation of the ions at lower temperatures, leading to the formation of ionic liquids. On the other hand, in \(\mathrm{SO}_{4}{ }^{2-}\), due to the higher charge density, the electrostatic forces are stronger, leading to higher lattice energies. This results in higher melting points and prevents the formation of ionic liquids at lower temperatures. Thus, it can be concluded that salts containing the tetrahedral polyatomic anion \(\mathrm{BF}_{4}^{-}\) form ionic liquids due to the more diffuse charges and lower lattice energies, whereas salts with the somewhat larger tetrahedral ion \(\mathrm{SO}_{4}{ }^{2-}\) do not form ionic liquids due to their higher charge density and lattice energies.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) is pressurized into liquid and stored in cylinders to be used as a fuel. The normal boiling point of propane is listed as \(-42^{\circ} \mathrm{C}\). (a) When converting propane into liquid at room temperature of \(25^{\circ} \mathrm{C},\) would you expect the pressure in the tank to be greater or less than atmospheric pressure? How does the pressure within the tank depend on how much liquid propane is in it? (b) Suppose the fuel tank leaks and a few liters of propane escape rapidly. What do you expect would happen to the temperature of the remaining liquid propane in the tank? Explain. (c) How much heat must be added to vaporize $20 \mathrm{~g}\( of propane if its heat of vaporization is \)18.8 \mathrm{~kJ} / \mathrm{mol} ?\( What volume does this amount of propane occupy at \)100 \mathrm{kPa}\( and \)25^{\circ} \mathrm{C} ?$

At room temperature, \(\mathrm{CO}_{2}\) is a gas, \(\mathrm{CCl}_{4}\) is a liquid, and \(\mathrm{C}_{60}\) (fullerene) is a solid. List these substances in order of (a) increasing intermolecular energy of attraction and (b) increasing boiling point.

Indicate whether each statement is true or false: (a) The liquid crystal state is another phase of matter, just like solid, liquid, and gas. (b) Liquid crystalline molecules are generally spherical in shape. (c) Molecules that exhibit a liquid crystalline phase do so at well-defined temperatures and pressures. (d) Molecules that exhibit a liquid crystalline phase show weaker-than- expected intermolecular forces. (e) Molecules containing only carbon and hydrogen are likely to form liquid crystalline phases. (f) Molecules can exhibit more than one liquid crystalline phase.

Rubbing alcohol is the common name for 2 -propanol (isopropanol), \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}\). (a) Draw the three-dimensional structure of the 2 -propanol molecule and predict the geometry around each carbon atom. (b) Is the 2 -propanol molecule polar or nonpolar? (c) What kinds of intermolecular attractive forces exist between the 2 -propanol molecules? (d) The isomer 1-propanol has the same molecular weight as 2 -propanol, yet 2 -propanol boils at \(82.6^{\circ} \mathrm{C}\) and 1 -propanol boils at \(97.2^{\circ} \mathrm{C}\). Explain the difference.

As a metal such as lead melts, what happens to (a) the average kinetic energy of the atoms and (b) the average distance between the atoms?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free