Which of the three-dimensional primitive lattices has a unit cell where none of the internal angles is \(90^{\circ}\) ? (a) Orthorhombic, (b) hexagonal, (c) rhombohedral, (d) triclinic, (e) both rhombohedral and triclinic.

Short Answer

Expert verified
The correct answer is (e) both rhombohedral and triclinic lattices, as they are the only ones among the given lattice types where none of the internal angles is equal to 90°.

Step by step solution

01

Orthorhombic lattice

In an orthorhombic lattice, all three axes are mutually perpendicular, which means that the internal angles are exactly 90°. So, an orthorhombic lattice does not match the required conditions.
02

Hexagonal lattice

In a hexagonal lattice, the angle between the a and b axes is 120°, while the angle between the a and c axes and between the b and c axes is 90°. By definition, the hexagonal lattice has at least one angle equal to 90°, so it doesn't satisfy the conditions.
03

Rhombohedral lattice

In a rhombohedral lattice, the angles between each pair of axes are equal and not 90° (they are equal to α). As this lattice has all internal angles not equal to 90°, it meets the required conditions. Therefore, it could be one of the answers.
04

Triclinic lattice

In a triclinic lattice, all three axes are different in length and the internal angles between them are α, β, and γ, where none of these angles is equal to 90°. Therefore, this lattice also meets the required conditions and could be another answer.
05

Both rhombohedral and triclinic

Since both rhombohedral and triclinic lattices meet the required conditions, the correct answer is (e) both rhombohedral and triclinic.

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