Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 12: Problem 86

Write a balanced chemical equation for the formation of a polymer via a condensation reaction from the monomers 1,4-phenylenediamine \(\left(\mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\right)\) and terephthalic acid $\left(\mathrm{HOOCC}_{6} \mathrm{H}_{4} \mathrm{COOH}\right)$

Short Answer

Expert verified
The balanced chemical equation for the formation of a polymer via a condensation reaction between 1,4-phenylenediamine $\left(\mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\right)$ and terephthalic acid $\left(\mathrm{HOOCC}_{6} \mathrm{H}_{4} \mathrm{COOH}\right)$ is: \( \mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH}_{2} + \mathrm{HOOCC}_{6} \mathrm{H}_{4} \mathrm{COOH \to [H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH - CO - C}_{6} \mathrm{H}_{4} \mathrm{CO]_n + \mathrm{H}_{2} \mathrm{O} \)

Step by step solution

01

Identify the reacting groups of the monomers

In the monomers, 1,4-phenylenediamine has two amino groups (-NH_2), and terephthalic acid has two carboxylic acid groups (-COOH). These groups will react to form an amide bond (-CONH-) and release a water molecule.
02

Write the chemical equation for the reaction

The condensation reaction between 1,4-phenylenediamine and terephthalic acid can be represented as: H_2NC_6H_4NH_2 + HOOC - C_6H_4 - COOH → [H_2NC_6H_4NH - CO - C_6H_4 - CO]n + H_2O Here, [H_2NC_6H_4NH - CO - C_6H_4 - CO]n represents the repeating unit of the polymer, and n is the degree of polymerization.
03

Balance the chemical equation

In this case, the chemical equation is already balanced as each side of the equation contains the same number of atoms for each element (2 H, 1 N, 4 C for the 1,4-phenylenediamine monomer and 8 H, 2 O, and 8 C for the terephthalic acid monomer). Therefore, the balanced chemical equation for the formation of the polymer via this condensation reaction is: H_2NC_6H_4NH_2 + HOOC - C_6H_4 - COOH → [H_2NC_6H_4NH - CON(C_6H_4)]n + H_2O

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which would you expect to be the more ductile element, (a) \(\mathrm{Ag}\) or \(\mathrm{Cr}\) (b) Zn or Ge? In each case explain your reasoning.

For each of the following pairs of semiconductors, which one will have the larger band gap: \((\mathbf{a})\) InP or InAs, \((\mathbf{b})\) Ge or AlP, (c) AgI or CdTe?

An ester is a compound formed by a condensation reaction between a carboxylic acid and an alcohol that eliminates a water molecule. Read the discussion of esters in Section 24.4 and then give an example of a reaction forming an ester. How might this kind of reaction be extended to form a polymer (a polyester)?

Calculate the volume in \(\AA^{3}\) of each of the following types of cubic unit cells if it is composed of atoms with an atomic radius of \(182 \mathrm{pm}\). (a) primitive (b) face-centered cubic.

Which statement correctly describes a difference between graphene and graphite? (a) Graphene is a molecule but graphite is not. (b) Graphene is a single sheet of carbon atoms and graphite contains many, and larger, sheets of carbon atoms. (c) Graphene is an insulator but graphite is a metal. (d) Graphite is pure carbon but graphene is not. \((\mathbf{e})\) The carbons are $s p^{2}\( hybridized in graphene but \)s p^{3}$ hybridized in graphite.
See all solutions

Recommended explanations on Chemistry Textbooks

Making Measurements

Read Explanation

Kinetics

Read Explanation

The Earths Atmosphere

Read Explanation

Chemical Reactions

Read Explanation

Chemical Analysis

Read Explanation

Organic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free