Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 12: Problem 93

If you want to make a polymer for plastic wrap, should you strive to make a polymer that has a high or low degree of crystallinity?

Short Answer

Expert verified
A polymer with a lower degree of crystallinity is more suitable for making plastic wrap, as it provides better flexibility, transparency, and ease of processing, which are essential for the functionality of plastic wrap.

Step by step solution

01

Define crystallinity

Crystallinity is the degree to which the polymer chains are organized in a regular and ordered structure. Some polymers exhibit crystalline regions, whereas others have an amorphous, disordered structure.
02

Understand the properties of high crystallinity polymers

Polymers with a high degree of crystallinity exhibit better mechanical strength, have higher melting points, and are more resistant to solvents and chemicals. However, they can be more brittle and less transparent.
03

Understand the properties of low crystallinity polymers

Polymers with a low degree of crystallinity, or with more amorphous regions, exhibit better clarity and transparency, are more flexible, and have a lower melting point. They may also have better resistance to cracking and are easier to process.
04

Evaluate the desired properties for plastic wrap

Plastic wrap is typically used to cover and protect food items, so it needs to be flexible, transparent, and capable of sealing. It also needs to adhere to a variety of surfaces to be effective. It should be able to be easily processed and manufactured economically.
05

Determine if high or low crystallinity is preferred for plastic wrap

Based on the desired properties of plastic wrap, a polymer with a lower degree of crystallinity is more suitable for this application. Low crystallinity polymers would provide better flexibility, transparency, and the ability to be processed easily, which are all essential for the functionality of plastic wrap.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Energy bands are considered continuous due to the large number of closely spaced energy levels. The range of energy levels in a crystal of copper is approximately \(1 \times 10^{-19} \mathrm{~J}\). Assuming equal spacing between levels, the spacing between energy levels may be approximated by dividing the range of energies by the number of atoms in the crystal. (a) How many copper atoms are in a piece of copper metal in the shape of a cube with edge length \(0.5 \mathrm{~mm}\) ? The density of copper is $8.96 \mathrm{~g} / \mathrm{cm}^{3}$. (b) Determine the average spacing in J between energy levels in the copper metal in part (a). (c) Is this spacing larger, substantially smaller, or about the same as the \(1 \times 10^{-18}\) J separation between energy levels in a hydrogen atom?

The densities of the elements Cr, Mn, Fe, and Cu are 7.15 , \(7.30,7.87,\) and \(8.96 \mathrm{~g} / \mathrm{cm}^{3}\), respectively. One of these elements crystallizes in a face-centered cubic structure; the other three crystallize in a body-centered cubic structure. Which one crystallizes in the face- centered cubic structure? Justify your answer.

Orange light-emitting diodes are made from GaAs and GaP solid solutions, \(\mathrm{GaP}_{x} \mathrm{As}_{1-x}\) (see Exercise 12.79). The original orange LEDs emitted light with a wavelength of \(590 \mathrm{nm}\). If we assume that the band gap varies linearly with composition between \(x=0\) and \(x=1\), estimate the composition (the value of \(x\) ) that is used in these LEDs.

Silicon is the fundamental component of integrated circuits. Si has the same structure as diamond. (a) Is Si a molecular, metallic, ionic, or covalent- network solid? (b) Silicon readily reacts to form silicon dioxide, \(\mathrm{SiO}_{2,}\) which is quite hard and is insoluble in water. Is \(\mathrm{SiO}_{2}\) most likely a molecular, metallic, ionic, or covalent- network solid?

The coordination number for the \(\mathrm{Al}^{3+}\) ion is typically between four and six. Use the anion coordination number to determine the \(\mathrm{Al}^{3+}\) coordination number in the following compounds: (a) \(\mathrm{AlF}_{3}\) where the fluoride ions are two coordinate, $(\mathbf{b}) \mathrm{Al}_{2} \mathrm{O}_{3}$ where the oxygen ions are six coordinate, \((\mathbf{c})\) AlN where the nitride ions are four coordinate.
See all solutions

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Chemistry Branches

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free