What is the osmotic pressure formed by dissolving \(50.0 \mathrm{mg}\) of acetylsalicylic acid $\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\right)\( in \)0.100 \mathrm{~L}\( of water at \)37^{\circ} \mathrm{C} ?$

Short Answer

Expert verified
The osmotic pressure formed by dissolving 50.0 mg of acetylsalicylic acid in 0.100 L of water at 37°C is approximately \(7.08 × 10⁻²\) atm.

Step by step solution

01

Calculate the molar mass of acetylsalicylic acid

To calculate the molar mass, we sum up the molar masses of all the atoms in acetylsalicylic acid (\(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\)). Molar mass of C: 12.01 g/mol Molar mass of H: 1.01 g/mol Molar mass of O: 16.00 g/mol Molar mass of acetylsalicylic acid = 9(12.01) + 8(1.01) + 4(16.00) = 180.16 g/mol
02

Determine the number of moles in the 50.0 mg sample

First, convert 50.0 mg to grams: 50.0 mg × 1 g/1000 mg = 0.0500 g Now, use the molar mass to find the number of moles: Number of moles = mass / molar mass = 0.0500 g / 180.16 g/mol = 2.77 × 10⁻⁴ mol
03

Calculate the molarity of the solution

Molarity (M) = number of moles / volume of solution in liters M = 2.77 × 10⁻⁴ mol / 0.100 L = 2.77 × 10⁻³ mol/L
04

Convert temperature from Celsius to Kelvin

To convert temperature from Celsius to Kelvin, we add 273.15 to the Celsius temperature: T(K) = 37°C + 273.15 = 310.15 K
05

Calculate the osmotic pressure

Use the osmotic pressure formula, remembering that van't Hoff factor (i) is 1 for non-electrolyte substances like acetylsalicylic acid: \( \Pi = iMRT \) Plug in the values: (M = 2.77 × 10⁻³ mol/L, R = 0.0821 L atm/mol K, and T = 310.15 K) \( \Pi = 1 × (2.77 × 10⁻³ \: \text{mol/L}) × (0.0821 \: \text{L atm/mol K}) × (310.15 \: \text{K}) \) \( \Pi = 7.08 × 10⁻² \: \text{atm} \) The osmotic pressure formed by dissolving 50.0 mg of acetylsalicylic acid in 0.100 L of water at 37°C is approximately 7.08 × 10⁻² atm.

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