Lysozyme is an enzyme that breaks bacterial cell walls. A solution containing \(0.150 \mathrm{~g}\) of this enzyme in \(210 \mathrm{~mL}\) of solution has an osmotic pressure of \(0.127 \mathrm{kPa}\) at \(25^{\circ} \mathrm{C}\). What is the molar mass of lysozyme?

Short Answer

Expert verified
The molar mass of lysozyme is approximately \(13.89 \frac{\mathrm{g}}{\mathrm{mol}}\).

Step by step solution

01

Write down the given information

We have the following information: - Mass of lysozyme: \(0.150 \mathrm{~g}\) - Volume of the solution: \(210 \mathrm{~mL}\) - Osmotic pressure: \(0.127 \mathrm{kPa}\) - Temperature: \(25^{\circ} \mathrm{C}\)
02

Convert the given information to appropriate units

We need to convert the temperature to Kelvin and the volume of the solution to liters: - Temperature in Kelvin: \(25^{\circ} \mathrm{C} + 273.15 = 298.15 \mathrm{K}\) - Volume of the solution in liters: \(\frac{210 \mathrm{~mL}}{1000} = 0.210 \mathrm{~L}\)
03

Use the osmotic pressure equation to solve for molar concentration

The osmotic pressure equation is given by: \(Π = \frac{n}{V} \times R \times T\) Where: - \(Π\) is the osmotic pressure - \(n\) is the number of moles of solute - \(V\) is the volume of the solution - \(R\) is the ideal gas constant (\(R = 8.314 \frac{\mathrm{J}}{\mathrm{mol \cdot K}}\)) - \(T\) is the temperature in Kelvin We can solve for the number of moles, \(n\), by re-arranging the equation: \(n = \frac{Π \times V}{R \times T}\) Now plug in the given values: \(n = \frac{0.127 \times 10^3 \times 0.210}{8.314 \times 298.15}\) \(n \approx 0.01080 \mathrm{~mol}\)
04

Calculate the molar mass

Now that we have the number of moles, we can calculate the molar mass by dividing the mass of lysozyme by the moles: Molar mass = \(\frac{mass}{moles}\) Molar mass = \(\frac{0.150 \mathrm{~g}}{0.01080 \mathrm{~mol}}\) Molar mass \(\approx 13.89 \frac{\mathrm{g}}{\mathrm{mol}}\) The molar mass of lysozyme is approximately \(13.89 \frac{\mathrm{g}}{\mathrm{mol}}\).

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