(a) Do colloids made only of gases exist? Why or why not? (b) In the 1850s, Michael Faraday prepared ruby-red colloids of gold nanoparticles in water that are still stable today. These brightly colored colloids look like solutions. What experiment(s) could you do to determine whether a given colored preparation is a solution or colloid?

Short Answer

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(a) Colloids made only of gases do not exist because gas particles freely mix with each other, rather than forming suspensions with a dispersed phase and dispersion medium. (b) To determine if a colored preparation is a solution or colloid, perform experiments like (1) observing the Tyndall effect, (2) filtration, and (3) sedimentation or centrifugation.

Step by step solution

01

Understand What Colloids Are

Colloids are a type of mixture that consists of two or more substances uniformly distributed throughout a powdery or granular substance or a liquid, but in which the individual particles do not dissolve, and instead are merely suspended (unlike solutions where the solute is dissolved). The size of particles in a colloid generally ranges between 1 nm and 1000 nm. The substance that is dispersed in a colloid is called the dispersed phase, and the medium in which it is dispersed is called the dispersion medium.
02

Determine if Colloids of Gases Exist and Explain Why

Colloids made only of gases do not exist because, in a gas, the particles are already in a state of continuous, random motion with large spaces between them. As a result, gas particles freely mix with each other, rather than forming a colloid in which particles remain suspended without dissolving. In a colloid made up of gas particles only, there would be no distinction between the dispersed phase and the dispersion medium because the particles would simply mix together instead of forming a suspension.
03

Identify Experiments to Determine if a Colored Preparation is a Solution or Colloid

To determine whether a given colored preparation is a solution or a colloid, one can perform the following experiments: 1. Tyndall effect: Shine a beam of light through the colored preparation and observe if the light path is visible or dispersed. In a colloid, the light path will be visible due to the scattering of light by the suspended particles (this is called the Tyndall effect). In a solution, the light path will not be visible, as the particles are dissolved and do not scatter light. 2. Filtration: Filter the colored preparation through a suitable filter paper. If the colored substance passes through the filter paper, it is a solution, as the dissolved particles are too small to be trapped in the filter. If the colored substance is retained by the filter paper, then it is a colloid, as the particles are larger and can be trapped in the filter. 3. Sedimentation and centrifugation: Allow the colored preparation to stand undisturbed for a suitable period of time. If the particles settle at the bottom, then it is a colloid. For faster results, centrifuge the sample. If particles are separated by centrifugation, it is a colloid. However, if the particles remain uniformly distributed and do not settle or separate, then it is a solution.

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Most popular questions from this chapter

An "emulsifying agent" is a compound that helps stabilize a hydrophobic colloid in a hydrophilic solvent (or a hydrophilic colloid in a hydrophobic solvent). Which of the following choices is the best emulsifying agent? (a) \(\mathrm{CH}_{3} \mathrm{COOH},\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH},\) (c) \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{11}\) COOH, (d) \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{11} \mathrm{COONa}\).

Which two statements about gas mixtures are true? [Section 13.1] (a) Gases always mix with other gases because the gas particles are too far apart to feel significant intermolecular attractions or repulsions. (b) Just like water and oil don't mix in the liquid phase, two gases can be immiscible and not mix in the gas phase. (c) If you cool a gaseous mixture, you will liquefy all the gases at the same temperature. (d) Gases mix in all proportions in part because the entropy of the system increases upon doing so.

Which of the following in each pair is likely to be more soluble in hexane, \(\mathrm{C}_{6} \mathrm{H}_{14}:\) (a) \(\mathrm{CCl}_{4}\) or \(\mathrm{CaCl}_{2}\), (b) benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) or glycerol, $\mathrm{CH}_{2}(\mathrm{OH}) \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{2} \mathrm{OH},\( (c) octanoic acid, \)\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH},$ or acetic acid, \(\mathrm{CH}_{3} \mathrm{COOH}\) ? Explain your answer in each case.

Common laboratory solvents include acetone $\left(\mathrm{CH}_{3} \mathrm{COCH}_{3}\right)\(, methanol \)\left(\mathrm{CH}_{3} \mathrm{OH}\right)\(, toluene \)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3}\right),$ and water. Which of these is the best solvent for nonpolar solutes?

A solution is made containing \(50.0 \mathrm{~g}\) of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) in \(1000 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O} .\) Calculate \((\mathbf{a})\) the mole fraction of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH},\) (b) the mass percent of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), (c) the molality of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\).

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