The enzyme urease catalyzes the reaction of urea, $\left(\mathrm{NH}_{2}
\mathrm{CONH}_{2}\right)$, with water to produce carbon dioxide and ammonia.
In water, without the enzyme, the reaction proceeds with a first-order rate
constant of \(4.15 \times 10^{-5} \mathrm{~s}^{-1}\) at $100^{\circ}
\mathrm{C}$. In the presence of the enzyme in water, the reaction proceeds
with a rate constant of \(3.4 \times 10^{4} \mathrm{~s}^{-1}\) at $21^{\circ}
\mathrm{C}$.
(a) Write out the balanced equation for the reaction catalyzed by urease.
\((\mathbf{b})\) If the rate of the catalyzed reaction were the same at
\(100^{\circ} \mathrm{C}\) as it is at \(21^{\circ} \mathrm{C}\), what would be
the difference in the activation energy between the catalyzed and uncatalyzed
reactions? (c) In actuality, what would you expect for the rate of the
catalyzed reaction at \(100^{\circ} \mathrm{C}\) as compared to that at
\(21^{\circ} \mathrm{C} ?(\mathbf{d})\) On the basis of parts (c) and (d), what
can you conclude about the difference in activation energies for the catalyzed
and uncatalyzed reactions?