(a) Can an intermediate appear as a reactant in the first step of a reaction mechanism? (b) On a reaction energy profile diagram, is an intermediate represented as a peak or a valley? (c) If a molecule like \(\mathrm{Cl}_{2}\) falls apart in an elementary reaction, what is the molecularity of the reaction?

Short Answer

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(a) No, an intermediate cannot appear as a reactant in the first step of a reaction mechanism, as it is formed and consumed during the reaction process. (b) An intermediate is represented as a valley on a reaction energy profile diagram. (c) The molecularity of the elementary reaction where \(\mathrm{Cl}_{2}\) falls apart is 1, making it a unimolecular reaction.

Step by step solution

01

Answer to part (a)

In a reaction mechanism, an intermediate is a species that is formed and consumed during the sequence of steps. It is important to note that intermediates are not present at the beginning or the end of the reaction. As such, it is not possible for an intermediate to appear as a reactant in the first step of a reaction mechanism because intermediate species must be formed from the reactants during the reaction process.
02

Answer to part (b)

On a reaction energy profile diagram, the progress of the reaction is represented along the horizontal axis, and the reaction energy is represented along the vertical axis. Transition states, which are the highest energy states along the reaction pathway, are represented as peaks, while reactants, products, and intermediates are represented as valleys. Therefore, an intermediate is represented as a valley on a reaction energy profile diagram.
03

Answer to part (c)

The molecularity of a reaction refers to the number of species involved in an elementary reaction step. In the case of a molecule like \(\mathrm{Cl}_{2}\) falling apart in an elementary reaction, the reaction can be represented as: \[ \mathrm{Cl}_{2} \rightarrow 2\,\mathrm{Cl} \] In this elementary reaction, only one molecule, \(\mathrm{Cl}_{2}\), is involved in the reaction process. As such, the molecularity of this reaction is 1, which means it is a unimolecular reaction.

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Most popular questions from this chapter

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