By what factor does \(\left[\mathrm{H}^{+}\right]\) change for a pH change of (a) 3.0 units, (b) 0.3 units?

Short Answer

Expert verified
The concentration of hydrogen ions (\([\mathrm{H}^{+}]\)) changes by a factor of (a) \(10^{-3}\) or \(0.001\) for a pH change of 3.0 units, and (b) \(10^{-0.3}\) or approximately \(0.501\) for a pH change of 0.3 units.

Step by step solution

01

Calculate the initial and final pH values

We are given that the pH change is 3.0 units. Let the initial pH be \(pH_{i}\) and the final pH be \(pH_{f}\). So, we can write \(pH_{f} = pH_{i} + 3\).
02

Use the pH formula to find the change in H+ concentration

We know that \(pH = -\log_{10}([\mathrm{H}^{+}])\). Thus, we have: Initial H+ concentration: \([\mathrm{H}^{+}]_{i}=10^{-pH_{i}}\) Final H+ concentration: \([\mathrm{H}^{+}]_{f}=10^{-pH_{f}}=10^{-(pH_{i}+3)}\)
03

Calculate the factor by which the H+ concentration changes

We have to find the factor \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}}\): \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = \frac{10^{-(pH_{i}+3)}}{10^{-pH_{i}}}\) By dividing exponents: \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = 10^{-3}\) So the H+ concentration changes by a factor of \(10^{-3}\) or \(0.001\). (b) For a pH change of 0.3 units:
04

Calculate the initial and final pH values

We are given that the pH change is 0.3 units. We can write \(pH_{f} = pH_{i} + 0.3\).
05

Use the pH formula to find the change in H+ concentration

We have: Initial H+ concentration: \([\mathrm{H}^{+}]_{i}=10^{-pH_{i}}\) Final H+ concentration: \([\mathrm{H}^{+}]_{f}=10^{-pH_{f}}=10^{-(pH_{i}+0.3)}\)
06

Calculate the factor by which the H+ concentration changes

We have to find the factor \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}}\): \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = \frac{10^{-(pH_{i}+0.3)}}{10^{-pH_{i}}}\) By dividing exponents: \(\frac{[\mathrm{H}^{+}]_{f}}{[\mathrm{H}^{+}]_{i}} = 10^{-0.3}\) So the H+ concentration changes by a factor of \(10^{-0.3}\) or approximately \(0.501\).

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