Predict whether aqueous solutions of the following substances are acidic, basic, or neutral: (a) \(\mathrm{AlCl}_{3},(\mathbf{b}) \mathrm{NaBr},\) (c) $\mathrm{NaClO},(\mathbf{d})\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right] \mathrm{NO}_{3},$ (e) \(\mathrm{Na}_{2} \mathrm{SO}_{3}\)

Short Answer

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(a) The aqueous solution of AlCl3 will be acidic. (b) The aqueous solution of NaBr is neutral. (c) The aqueous solution of NaClO is basic. (d) The aqueous solution of \(\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right]\mathrm{NO}_{3}\) will be acidic. (e) The aqueous solution of \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) is basic.

Step by step solution

01

(a) Analyzing AlCl3

Aluminum chloride, \(\mathrm{AlCl}_{3}\), forms an Al\(^{3+}\) ion and three Cl\(^-\) ions when dissolved in water. The Al\(^{3+}\) ion is a Lewis acid, and it will react with water molecules to form Al(H\(_2\)O)\(_3^{3+}\) and release H\(^+\) ions into the solution, increasing the acidity. The Cl\(^-\) ions are mostly spectator ions that do not affect acidity/basicity. Therefore, an aqueous solution of AlCl3 will be acidic.
02

(b) Analyzing NaBr

Sodium bromide, NaBr, forms a Na\(^+\) ion and a Br\(^-\) ion when dissolved in water. The Na\(^+\) ions are spectactor ions that do not affect acidity/basicity. The Br\(^-\) ion is a conjugate base of a strong acid, HBr, and it will not hydrolyze to form a significant amount of hydroxide ions. Therefore, the aqueous solution of sodium bromide is neutral.
03

(c) Analyzing NaClO

Sodium hypochlorite, NaClO, forms a Na\(^{+}\) ion and a ClO\(^{-}\) ion when dissolved in water. The Na\(^{+}\) ions are spectator ions and do not affect acidity/basicity. The ClO\(^-\) ion is a conjugate base of a weak acid, HOCl, so it will hydrolyze to produce OH\(^{-}\) ions in solution. Therefore, the aqueous solution of sodium hypochlorite is basic.
04

(d) Analyzing CH3NH3NO3

Methylammonium nitrate, \(\left[\mathrm{CH}_{3} \mathrm{NH}_{3}\right]\mathrm{NO}_{3}\), forms a CH\(_3\)NH\(_3^{+}\) ion and a NO\(_3^-\) ion when dissolved in water. The CH\(_3\)NH\(_3^{+}\) ion is a conjugate acid of a weak base, CH\(_3\)NH\(_2\), and it will release H\(^+\) ions in solution. The NO\(_3^-\) ion is a conjugate base of a strong acid, HNO\(_3\), and it will not hydrolyze to form a significant amount of hydroxide ions. Thus, the aqueous solution of methylammonium nitrate will be acidic.
05

(e) Analyzing Na2SO3

Sodium sulfite, \(\mathrm{Na}_{2} \mathrm{SO}_{3}\), forms two Na\(^+\) ions and one SO\(_3^{2-}\) ion when dissolved in water. The Na\(^+\) ions are spectator ions that do not affect acidity/basicity. The SO\(_3^{2-}\) ion is a conjugate base of a weak acid, HSO\(_3^-\), and it will hydrolyze to produce OH\(^{-}\) ions in solution. Therefore, the aqueous solution of sodium sulfite is basic.

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Most popular questions from this chapter

An unknown salt is either $\mathrm{KBr}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{KCN},\( or \)\mathrm{K}_{2} \mathrm{CO}_{3} .\( If a \)0.100 \mathrm{M}$ solution of the salt is neutral, what is the identity of the salt?

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