An unknown salt is either $\mathrm{KBr}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{KCN},\( or \)\mathrm{K}_{2} \mathrm{CO}_{3} .\( If a \)0.100 \mathrm{M}$ solution of the salt is neutral, what is the identity of the salt?

Short Answer

Expert verified
The identity of the unknown salt that forms a neutral 0.100 M solution is KBr (potassium bromide), as both ions, \(\mathrm{K^+}\) and \(\mathrm{Br^-}\), do not affect the pH of the solution.

Step by step solution

01

Determine the ions in the solution for each salt

When a salt is dissolved in water, it dissociates into its ions. For each salt, we can write: 1. KBr: \(\mathrm{K^+}\) and \(\mathrm{Br^-}\) 2. NH\(_4\)Cl: \(\mathrm{NH_4^+}\) and \(\mathrm{Cl^-}\) 3. KCN: \(\mathrm{K^+}\) and \(\mathrm{CN^-}\) 4. K\(_2\)CO\(_3\): \(\mathrm{2K^+}\) and \(\mathrm{CO_3^{2-}}\)
02

Investigate the effect of each ion on the pH of the solution

For each of the ions in the solution, we will determine whether it will increase, decrease, or not affect the pH: 1. \(\mathrm{K^+}\): This is a Group 1 (alkali metal) cation and will not affect the pH of the solution. 2. \(\mathrm{Br^-}\): As the conjugate base of a strong acid (HBr), it will not affect the pH of the solution. 3. \(\mathrm{NH_4^+}\): This is the ammonium ion, which is the conjugate acid of a weak base (NH\(_3\)). It will slightly decrease the pH of the solution. 4. \(\mathrm{Cl^-}\): Like Br\(^-\), as the conjugate base of a strong acid (HCl), it will not affect the pH of the solution. 5. \(\mathrm{CN^-}\): This is the cyanide ion, which is the conjugate base of a weak acid (HCN). It will slightly increase the pH of the solution. 6. \(\mathrm{CO_3^{2-}}\): This is the carbonate ion, which is the conjugate base of a weak acid (H\(_2\)CO\(_3\)). It will increase the pH of the solution.
03

Identify the neutral salt

Now we must identify which combination of cations and anions will produce a neutral solution: 1. KBr: \(\mathrm{K^+}\) does not affect the pH and \(\mathrm{Br^-}\) does not affect the pH. 2. NH\(_4\)Cl: \(\mathrm{NH_4^+}\) decreases the pH and \(\mathrm{Cl^-}\) does not affect the pH. 3. KCN: \(\mathrm{K^+}\) does not affect the pH and \(\mathrm{CN^-}\) increases the pH. 4. K\(_2\)CO\(_3\): \(\mathrm{2K^+}\) does not affect the pH and \(\mathrm{CO_3^{2-}}\) increases the pH. From our analysis, only the KBr salt has both ions that do not affect the pH, which means it will produce a neutral solution when dissolved in water.
04

Conclusion

The identity of the unknown salt that forms a neutral 0.100 M solution is KBr (potassium bromide), as both ions do not affect the pH of the solution.

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Most popular questions from this chapter

Oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) is a diprotic acid. By using data in Appendix \(\mathrm{D}\) as needed, determine whether each of the following statements is true: (a) \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) can serve as both a Bronsted-Lowry acid and a Brønsted-Lowry base. (b) $\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\( is the conjugate base of \)\mathrm{HC}_{2} \mathrm{O}_{4}^{-}$. (c) An aqueous solution of the strong electrolyte \(\mathrm{KHC}_{2} \mathrm{O}_{4}\) will have \(\mathrm{pH}<7\).

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