Do the reactions involved in ozone depletion involve changes in oxidation state of the O atoms? Explain.

Short Answer

Expert verified
Yes, the reactions involved in ozone depletion involve changes in the oxidation state of Oxygen atoms. During the chlorine-catalyzed ozone depletion process, the oxidation state of one Oxygen atom changes from -1 to 0.

Step by step solution

01

Understand the ozone depletion process

Ozone depletion occurs when certain chemicals, such as chlorine-containing substances, destroy ozone molecules in the stratosphere, reducing the earth's protective ozone layer. The most common substances that cause ozone depletion are chlorofluorocarbons (CFCs) and other halogenated compounds.
02

Write down the chlorine-catalyzed ozone depletion reactions

The process of chlorine-catalyzed ozone depletion can be represented by the following two reactions: (1) Cl + O₃ → ClO + O₂ (2) ClO + O → Cl + O₂ The overall reaction is the sum of the two above: O₃ + O → 2O₂
03

Determine the oxidation states of Oxygen atoms

Oxidation state represents the number of electrons that an atom can gain or lose in a chemical reaction to form a bond with one or more atoms. Determine the oxidation states of Oxygen atoms in different molecules involved in the chlorine-catalyzed ozone depletion reactions, starting with ozone (O₃): - In O₃, the central Oxygen atom bonds with two external Oxygen atoms. The central Oxygen atom has an oxidation state of 0, while each external Oxygen atom has an oxidation state of -1. Now, let's look at the products after the first reaction: - In O₂, each Oxygen atom has an oxidation state of 0, as it forms a double bond with another Oxygen atom. - In ClO, the Chlorine atom has an oxidation state of +1, and the Oxygen atom has an oxidation state of -1. Looking at the products after the second reaction: - In O₂, each Oxygen atom has an oxidation state of 0. - In Cl, the Chlorine atom has an oxidation state of 0, and in O, the single Oxygen atom has an oxidation state of 0 as well.
04

Analyze the changes in oxidation states

Let's analyze the changes in the oxidation states for Oxygen atoms during the two reactions: - In reaction (1), the central Oxygen atom in O₃ (oxidation state 0) becomes part of an O₂ molecule (oxidation state 0), and one of the external Oxygen atoms in O₃ (oxidation state -1) becomes part of ClO (oxidation state -1). There are no changes in the oxidation state for the Oxygen atoms involved in this reaction. - In reaction (2), the Oxygen atom in ClO (oxidation state -1) becomes part of an O₂ molecule (oxidation state 0), and the single Oxygen atom involved in the reaction (oxidation state 0) also becomes part of an O₂ molecule (oxidation state 0). Only one Oxygen atom changes its oxidation state, from -1 to 0.
05

Answer the question

Do the reactions involved in ozone depletion involve changes in the oxidation state of the O atoms? Yes, during the chlorine-catalyzed ozone depletion process, the oxidation state of one Oxygen atom changes from -1 to 0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One of the principles of green chemistry is that it is better to use as few steps as possible in making new chemicals. In what ways does following this rule advance the goals of green chemistry? How does this principle relate to energy efficiency?

Draw the Lewis structure for the chlorofluorocarbon CFC-11, \(\mathrm{CFCl}_{3}\). What chemical characteristics of this substance allow it to effectively deplete stratospheric ozone?

Suppose that on another planet the atmosphere consists of $10 \% \mathrm{Kr}, 40 \% \mathrm{CH}_{4},\( and \)50 \% \mathrm{O}_{2} .$ What is the average molar mass at the surface? What is the average molar mass at an altitude at which all the \(\mathrm{O}_{2}\) is photodissociated?

The estimated average concentration of \(\mathrm{NO}_{2}\) in air in the United States in 2015 was 0.010 ppm. (a) Calculate the partial pressure of the \(\mathrm{NO}_{2}\) in a sample of this air when the atmospheric pressure is \(101 \mathrm{kPa} .(\mathbf{b})\) How many molecules of \(\mathrm{NO}_{2}\) are present under these conditions at \(25^{\circ} \mathrm{C}\) in a room that measures \(10 \mathrm{~m} \times 8 \mathrm{~m} \times 2.50 \mathrm{~m} ?\)

The enthalpy of evaporation of water is \(40.67 \mathrm{~kJ} / \mathrm{mol}\). Sunlight striking Earth's surface supplies \(168 \mathrm{~W}\) per square meter \((1 \mathrm{~W}=1 \mathrm{watt}=1 \mathrm{~J} / \mathrm{s}) .(\mathbf{a})\) Assuming that evaporation of water is due only to energy input from the Sun, calculate how many grams of water could be evaporated from a 1.00 square meter patch of ocean over a 12 -h day. (b) The specific heat capacity of liquid water is \(4.184 \mathrm{~J} / \mathrm{g}^{\circ} \mathrm{C}\). If the initial surface temperature of a 1.00 square meter patch of ocean is $26^{\circ} \mathrm{C}\(, what is its final temperature after being in sunlight for \)12 \mathrm{~h}$, assuming no phase changes and assuming that sunlight penetrates uniformly to depth of \(10.0 \mathrm{~cm} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free